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1 year ago

How can you use bar diagrams to show a percent of change?

Mathematics

2 answers:

WINSTONCH [101]1 year ago

8 0

Answer:

Step-by-step explanation: here is a video that you can watch, that will answer your question (Solve Percent Problems Using a Tape Diagram (Bar Diagram) ) and search this

a_sh-v [17]1 year ago

7 0

Add and subtract hope this helps

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What strategy would you use to solve these facts involving 3 and 7? 8 x 3 7 x 4

iVinArrow [24]

$8\cdot3=7\cdot3+3\\ 7\cdot4=7\cdot3+7$

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3 years ago

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Divide using long division. <img src="https://tex.z-dn.net/?f=%282x%5E%7B3%7D%20%2B5x%5E%7B2%7D%20%20-7x%2B6%29" id="Tex

babunello [35]

Answer:

The quotient = 2x - 1 and the remainder = 4x + 2

Step-by-step explanation:

$\frac{2x^{3}+5x^{2}-7x+6}{x^{2}+3x-4}=2x+\frac{-x^{2}+x+6}{x^{2}+3x-4}$

$\frac{-x^{2}+x+6 }{x^{2}+3x-4}=-1+\frac{4x+2}{x^{2}+3x-4}$

The quotient = 2x - 1 and the remainder = 4x + 2

3 0

3 years ago

In a recent year, a poll asked 2362 random adult citizens of a large country how they rated economic conditions. In the poll,

Harman [31]

Answer:

a) The 99% confidence interval is given by (0.198;0.242).

b) Based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

c) $\alpha=0.01$

Step-by-step explanation:

Data given and notation

n=2362 represent the random sample taken

X represent the people who says that they would watch one of the television shows.

$\hat p=\frac{X}{n}=0.22$ estimated proportion of people rated as Excellent/Good economic conditions.

$p_o=0.24$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that 24% of people are rated with good economic conditions:

Null hypothesis: $p=0.24$

Alternative hypothesis: $p \neq 0.24$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Part a: Test the hypothesis

Check for the assumptions that he sample must satisfy in order to apply the test

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

np = 2362x0.22=519.64>10 and n(1-p)=2364*(1-0.22)=1843.92>10

Condition satisfied.

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.22 -0.24}{\sqrt{\frac{0.24(1-0.24)}{2362}}}=-2.28$

The confidence interval would be given by:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The critical value using $\alpha=0.01$ and $\alpha/2 =0.005$ would be $z_{\alpha/2}=2.58$ . Replacing the values given we have:

$0.22 - (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.198$

$0.22 + (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.242$

So the 99% confidence interval is given by (0.198;0.242).

Part b

Statistical decision 

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided is $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

Part c

The confidence level assumed was 99%, so then the signficance is given by $\alpha=1-confidence=1-0.99=0.01$

6 0

3 years ago

2.When I walked into King Soopers yesterday, I noticed that the Colorado Rockies t-shirts had a sign reading “25% off sale!”. If

daser333 [38]

Given:

The discount is 25%.

The selling price of the shirt after the sale is $20.99.

To find:

The selling price of the shirt before the sl;e

Explanation:

Let the old price be x.

The equation can be framed as follows,

$\begin{gathered} (\frac{100-25}{100})\times x=20.99 \\ \frac{75}{100}\times x=20.99 \\ x=20.99\times\frac{100}{75} \\ x=27.986 \\ x\approx27.99 \end{gathered}$

Final answer:

The selling price of the shirt before the sale is $27.99.

4 0

1 year ago

I need the answers please

Nadusha1986 [10]

base times height divided by 2

8 time 6 is 48 divided by 2 is 24

8 0

3 years ago

Read 2 more answers