Hello,
Rectangle A: 6cm (x+2)cm
Rectangle B: 3cm (2x+1)cm
The formula for the perimeter of a rectangle is: P=2(base+height)
Then:
![P_A=2(b+h) \\ P_A=2*[6+(x+2)] \\ P_A=2*(x+8) \\ P_A=2x+16 \\ \\ \\ P_B=2(b+h) \\ P_B=2*[3+(2x+1)] \\ P_B=2*(2x+4) \\ P_B=4x+8 ](https://tex.z-dn.net/?f=P_A%3D2%28b%2Bh%29%20%5C%5C%20P_A%3D2%2A%5B6%2B%28x%2B2%29%5D%20%5C%5C%20P_A%3D2%2A%28x%2B8%29%20%5C%5C%20P_A%3D2x%2B16%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20P_B%3D2%28b%2Bh%29%20%5C%5C%20P_B%3D2%2A%5B3%2B%282x%2B1%29%5D%20%5C%5C%20P_B%3D2%2A%282x%2B4%29%20%5C%5C%20P_B%3D4x%2B8%0A)
But we know that the perimeters are the same, so:
With the answer of A, we realize that this figure is actually a square.
Answer:221 miles
Step-by-step explanation:
4.25 x 52= 221
Answer:
Step-by-step explanation:
Since the buoy is going up and down, its motion is oscillatory, and therefore, it can be described by a trigonometric function.
The buoy starts at height of 0 in relation to the sea level, which means at time 
, 
, this tells us that trigonometric function modeling the buoy must be the sine function since for
, at , .
The maximum displacement of the buoy in either direction is 6 feet, this means we have
now we need to figure out 
.
The time it takes the buoy to get from its lowest point to its highest point is 4 seconds, that means the period 
of oscillation is 
seconds. The buoy returns to to the same place after one period, this means if the buoy started from 0, it will return to 0 after 8 seconds; therefore, from the we have:
Now the final equation looks like
Your welcome I’m glad to help out
Answer:
∠LPN = 57°
Step-by-step explanation:
arc LMN = 360° - 102° - 144° = 114°
∠LPN = 114°/2 = 57°
