Question

What is the vertex of the function?

Answer 1

Explanation:

Here you haven't provided any function, so I'll assume this one:

$f(x)=3x^2-18x+33$

This is a quadratic function whose graph represents a parabola. Any parabola has its vertex at the point:

$V(x,y) \\ \\ \\ x=-\frac{b}{2a} \\ \\ y=f(-\frac{b}{2a}) \\ \\ \\ where: \\ \\ \\ f(x)=ax^2+bx+c \\ \\ \\ So: \\ \\ a=3 \\ \\ b=-18 \\ \\ c=33$

Therefore:

$x=-\frac{(-18)}{2(3)}=3 \\ \\ f(3)=3(3)^2-18(3)+33=27-54+33=6$

Therefore, the vertex is:

$\boxed{V(3,6)}$