Answer:
The chosen topic is not meant for use with this type of problem. Try the examples below.
|2y| = 3 + 2
− 2 (y+2) = 2 −y
x−2=4
Step-by-step explanation:
50%. students (in percent) who passed the second exam also passed the first exam.
Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.
Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.
Thus, both tests were passed by 40 of the 80 pupils who passed the second one:
40/80 = 1/2 = 50%.
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Answer:
3:36PM
Step-by-step explanation:
Leon starts at 12PM with 12 gallons of gas, and after 2 hours he has used 5 gallons of gas. This means that every 2 hours he uses 5 gallons of gas.
Next we will find at what point Leon will stop to get gas. Since he will stop when the tank is at 
capacity, we can use the equation:
This shows of his tank's capacity (
) is equal to 
gallons. This means he will stop for gas when gallons are remaining.
Now we need to find how many gallons of gas he uses, but as a unit rate. (This will allow us to find what time Leon will stop to get gas.) To find the unit rate, we will need to find how many gallons of gas he uses per hour.
This is a simple proportion, and now we know he uses 
gallons of gas per hour.
Now we can how many hours of gas Leon has left.
He has 
gallons of gas left at 2PM, so we can divide to find how many hours left of gas he has.
The 
is because Leon doesn't stop when his tank is empty, he stops gallons earlier. We are dividing by because that is how much gas he uses per hour, meaning the result of this division (
) is how many hours he has left.
Now we can solve for what time Leon will stop to get gas.
12PM + 
hours of driving + the remaining hours = 3:36PM
( hours is equal to 1 hour and 36 minutes)
Therefore, Leon will stop for gas at 3:36PM
This is a geometric sequence because each term is twice the value of the previous term. So this is what would be called the common ratio, which in this case is 2. Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number
In this case we have r=2 and a=1 so
a(n)=2^(n-1) so on the sixth week he will run:
a(6)=2^5=32
He will run 32 blocks by the end of the sixth week.
Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) where the variables have the same values so
s(n)=(1-2^n)/(1-2)
s(n)=2^n-1 so
s(6)=2^6-1
s(6)=64-1
s(6)=63 blocks
So he would run a total of 63 blocks in the six weeks.
Slope, shmlope. What's the q?
