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Natasha2012 [34]
3 years ago
14

For what values of m does the graph of y = mx2 – 5x – 2 have no x-intercepts?

Mathematics
1 answer:
Naya [18.7K]3 years ago
8 0
Take a look at   <span>y = mx^2 – 5x – 2.   This is a quadratic equation with a=m, b= -5 and c= -2.  What is the discriminant, b^2 - 4ac?  (-5)^2 - 4(m)(-2).

There will be 2 complex roots if this discrim. is < 0.  Thus, solve 

25 + 8m < 0:   

Subtr. 25 from both sides:              8m < -25
Div. both sides by 8:                         m < -25/8

Conclusion:  If m is less than -25/8, there will be no real roots (and thus, no x-intercepts). </span>
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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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vova2212 [387]
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Step-by-step explanation:

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