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NARA [144]
3 years ago
14

Find the surface area of the solid figure represented by the given net. 10cm squared 10cm squared 10cm squared 10cm squared 25cm

squared
Mathematics
2 answers:
m_a_m_a [10]3 years ago
7 0

Answer:

its actually 65

Step-by-step explanation:

Vika [28.1K]3 years ago
5 0

GIVEN:

Side = 5cm.

FORMULA:

Surface area of cube = 6side²

ANSWER:

We know the formula,

so SA = 6 × (5)²

  • 6 × 25
  • 150cm².

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Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and st
SashulF [63]

Answer:

0.7233

Step-by-step explanation:

We want to find the area between the z-scores z=-0.95 and z=1.25.

We first find the area to the left of each z-score, and subtract the smaller area from the bigger one.

For the area to the left of z=-0.95, we read -0.9 under 5 from the standard normal distribution table.

This gives P(z<-0.95)=0.1711

Similarly the area to the left of z=1.25 is

P(z<1.25)=0.8944

Now the area between the two z-scores is

P(-0.25<z<1.25)=0.8944-0.1711=0.7233

7 0
3 years ago
On a sunny day, a flag pole and its shadow form the sides of a right triangle. if the hypotenuse is 35 meters long and the shado
Triss [41]
We can use Pythagorean's Theorem in order to find the remaining side length
a^2+b^2=c^2
Let a be the shadow length
Let b be the height of the flagpole
Let c be the hypotenuse 
28^2+b^2=35^2
784+b^2=1225
b^2=1225-784
b^2=441
b=√441
b=21
Therefore the flagpole is 21 meters tall.
Hope this helps!
 
 
3 0
3 years ago
Help I need it I’m almost done
sesenic [268]

Answer:

E

Step-by-step explanation:

3 0
3 years ago
Jocelyn estimates that a piece of wood measures 5.5 cm. If it actually measures 5.62, what is the percent error of Jocelyns esti
goldenfox [79]

Answer:    The percent error is -2.1352% of Jocelyn's estimate.

7 0
3 years ago
ANHL player's labor negotiating committee is to be selected from 8 player representatives from the Eastern Conference and 7 play
cestrela7 [59]

Answer:

21 / 143

Step-by-step explanation:

Given that:

Number of Eastern conference reps = 8

Number of western conference rep = 7

Probability of selecting 3 from Eastern reps and 2 from western reps

Probability = required outcome / Total possible outcomes

Total possible outcomes:

selection to be made = 3+ 2 = 5

Total Number of players = 8 +7 = 15

Total possible outcomes

Using combination formula :

nCr = n! / (n-r)!r!

15C5 = 15! / 10!5! = (15 * 14 * 13 * 12 * 11) / (5*4'3*2*1) = 360360 / 120 = 3003

Total possible outcomes = 3003

Required outcome :

8C3 * 7C2

8C3 = 56 ; 7C2 = 21

8C3 * 7C2 = 56 * 21 = 1176

required outcome / Total possible outcomes

= 1176 / 3003

= 21 / 143

6 0
3 years ago
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