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3 years ago

Find XY. ._______._. X Y 7 Z

Mathematics

1 answer:

Rufina [12.5K]3 years ago

6 0

Answer:

hey dude, The formula is (x-y)³=x³-3x²y+3xy²-y³.

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Help me i’m in need

gtnhenbr [62]

<h3>Answer:</h3><h3>D</h3><h3 /><h3>Step-by-step explanation:</h3><h3></h3><h3>In a function, an input (x) value should have only one output (y) value.</h3><h3 />

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<em>Example: (View attached image below). </em><em>Table A</em><em> is a function because each </em><em>x </em><em>value has only 1 </em><em>y</em><em> value. But </em><em>Table B</em><em> is not a function because the </em><em>x value</em><em> of </em><em>4 </em><em>has </em><em>2 y values</em><em>.</em>

6 0

4 years ago

Read 2 more answers

9x-6+11x what would the answer be

frez [133]

Answer:

20x-6

Step-by-step explanation:

5 0

3 years ago

Helen [10]

Answer:

1. ΔUJN ≅ ΔUGN by SAS rule of congruency

2. Side Angle Side Rule of congruency

3. JN ≅ GN, ∠JUN ≅ ∠NUG, ∠UNJ ≅ ∠UNG, NU ≅ NU

4. UN bisects angle ∠JUG and UN bisects segment JG

Step-by-step explanation:

The given figure consists of three triangles

1. ΔUJN, 2. ΔUGN, and 3. ΔUJG

Whereby segment UN is perpendicular to segment JG, we have;

ΔUJN and ΔUGN are right triangles

∴ ∠UNJ = ∠UNG = 90° by definition of segment UN being perpendicular to segment JG

NU ≅ NU by reflexive property

Whereby UN bisects ∠JUG and segment JG, we have;

JN = GN by definition of a bisected segment

Therefore, we have;

1. ΔUJN ≅ ΔUGN by SAS rule of congruency

2. Side Angle Side Rule of congruency

3. JN ≅ GN, ∠JUN ≅ ∠NUG, ∠UNJ ≅ ∠UNG, NU ≅ NU

4. UN bisects angle ∠JUG and UN bisects segment JG

7 0

3 years ago

Factor completely 56a2b3 − 35ab.

VMariaS [17]

I would start off by taking away 1a. That would make the problem be 56ab3-35b.I only took away 1 because each have at least 1a and is okay to do.

Next I would deal with the variable b. I would cross of 1 b. That's because both sides have at least 1b. Now, it's shortened to be 56ab2-35.

Since you cannot take away anymore variables, you have to deal with 56 and 35. I start small with dividing each by 2. I am trying to see what the greatest number could be while making the numbers still be whole. That turns 56 into 28 when it's cut in half. The 35 now turns into 17.5.

I would assume your teacher would want the numbers to be whole. seeing as though when 35 is cut in half and makes a decimal number, I would leave them. What I mean by that is to leave the numbers as 56 and 35.

So, that means the answer is 56ab2-35.

I hope this helps!! (And makes sense)

5 0

3 years ago

the first 10 games played of the football season how many outcome possibilities are there if the total score of each game is ove

Dmitry_Shevchenko [17]

300 total point
since there r 10 games and 30 points fatal each game then it’s 300

5 0

3 years ago

Find XY. ._________.___. X Y 7 Z

Find XY. ._______._. X Y 7 Z