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Shtirlitz [24]
3 years ago
7

Select the correct answer from the drop-down menu. Find the product. The product of 2/5a2x and -1/5x2a is

Mathematics
2 answers:
Gemiola [76]3 years ago
7 0

Answer:

(2/5a²x)( -1/5x²a) = -2/25a³x³

Step-by-step explanation:

We have given two terms.

2/5a²x and -1/5x²a

We have to find product of given terms.

We use following formula to solve this.

yᵃyᵇ = yᵃ⁺ᵇ

The product is:

(2/5a²x)( -1/5x²a) =2/5a²x . -1/5x²a

Combining like terms, we have

(2/5a²x)( -1/5x²a) = (2/5)(-1/5)(a²a)(xx²)

(2/5a²x)( -1/5x²a) = (-2/25)(a²⁺¹)(x¹⁺²)

(2/5a²x)( -1/5x²a) =( -2/25)(a³)(x³)

(2/5a²x)( -1/5x²a) = -2/25a³x³

valentinak56 [21]3 years ago
3 0

Answer: -\frac{2}{25}a^{3}x^{3}

Step-by-step explanation:

1. The problem asked for the product of \frac{2}{5}a^{2}x and -\frac{1}{5}x^{2}a, therefore, you must mutliply them, as you can see below:

2. According the exponents propertiess, when you have a multiplication of two powers that has the equal base, you must add the exponents. THerefore, you have the following result:

 (\frac{2}{5}a^{2}x)(-\frac{1}{5}x^{2}a)=-\frac{2}{25}a^{3}x^{3}

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The Johnson twins were born eleven years after their older sister. This​ year, the product of the three​ siblings' ages is exact
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So there are 3 siblings: the first twin, the second twin, and their older sister.

Since the sister is older by 11 years, you can represent their relationship with the following equation;
age of twin = age of older sister - 11
t = s - 11

Representing this next part may be a little hard to show, but i'll do my best :)

Adding the ages together can be represented like this;
total age = t + t + s
If the product of their ages ( t * t * s ) is 1181 more than the sum, you can show it like this:
t * t * s = (t + t + s) + 1181
Now you substitute in (s - 11) for t because s = t - 11.
t * t * s = (t + t + s) + 1181\\&#10;(s-11) * (s-11) * s = ((s-11) + (s-11) + s) + 1181\\&#10;(s^{2}-22x+121)*s=s+s-11-11+1181\\&#10;s^{3}-22s^{2}+121s-2s=1159\\&#10;s^{3}-22s^{2}+118s-1159=0
Factor:
Since it's a third-degree equation, I just entered it into a polynomial solver in my calculator. There was only one factor listed, x = 19. Using (s - 19) = 0 as a factor, the equation becomes the following:
s^{3}-22s^{2}+118s-1159=0\\&#10;(s-19)(s^{2}-3s+61)=0
Using the quadratic formula, you get:
s= \frac{-b(+-)\sqrt{b^{2}-4ac}}{2a}\\&#10;s= \frac{-(-3)(+-)\sqrt{(-3)^{2}-4(1)(61)}}{2*1}\\&#10;s= \frac{3(+-)\sqrt{(9)-244}}{2}\\&#10;s= \frac{3(+-)\sqrt{-235}}{2}

Since you have a square root of a negative number, the answer will be imaginary. You cannot have an age that is imaginary, so the age of the older sister (s) is 19 years.

Because t = s - 11, that means that t = (19) - 11 = 8.
t is the age of the twins, so the twins are 8 years old.
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