Find the locus of a point P such that its ordinate is equal to the abscissa. Hence required equation of the locus of point P is y = 5x + 9. Hence required equation of the locus of point P is x = 2y + 3.
i write everything in the exploration
Step-by-step explanation:
MN=31
KN=45
K=61°
L=119°
M=61°
CF=10
FE=15
CE=14
GD=11
QR=19
SR=24
PT=21
SQ=20
QRS=70°
PQS=53°
RPS=35°
PSQ=53°
7x-2=12x-22
-2=5x-22
20=5x
x=4
7×4-2=26 (12×4-22=26)
(2x+11)×2=8x-14
4x+22=8x-14
22=4x-14
36=4x
x=9
( (2×9+11)×2=58. 8×9-14=58. so it's correct)
(3x+5)+(9x-17)=180
12x-12=180
12x=192
x=16
( (3×16+5)+(9×16-17)=53+127=180 so it's correct)
10x-27=2x+29
8x-27=29
8x=56
x=7
10×7-27=43 (2×7+29=43)
V=180-43°=137°
The answer id 12 meters.divide -2x^2+20x+48 by 2 to get x alone and then umbrella
Answer:
2
Step-by-step explanation:
Plug 4 in for d and 3 in for c
5d-2/3c
5(4)-2/3(3)
Multiply in the numerator and the denominator
20-2/9
Subtract in the numerator
18/9
2
Hope this helps! :)