Consider the attached ellipse. Let the sun be at the right focus. Then perihelion is at right vertex on the x-axis and aphelion is at the left vertex on the x-axis.

The distances:

from perihelion to the sun in terms of ellipse is a-c;
from aphelion to the sun in terms of ellipse is a+c.

Then

$\left\{\begin{array}{l}a-c=741,000,000\\a+c=817,000,000\end{array}\right.$

Add these two equations:

$2a=1,558,000,000 \\ \\a=779,000,000$

and subtract first equation from the second:

$2c=76,000,000 \\ \\c=38,000,000.$

Note that $b=\sqrt{a^2-c^2},$ thus

$b=\sqrt{779,000,000^2-38,000,000^2}=\sqrt{605,397,000,000,000,000}.$

The equation for the planet's orbit is

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\Rightarrow \dfrac{x^2}{606,841,000,000,000,000}+\dfrac{y^2}{605,397,000,000,000,000}=1.$

7 0

3 years ago

What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 > 15?

jolli1 [7]

Answer:

A. d ≤ –7 or d > 8.

Step-by-step explanation:

Given : 2d + 3 ≤ –11 or 3d – 9 > 15.

To find : What are the solutions of the compound inequality .

Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.

For 2d + 3 ≤ –11

On subtracting both sides by 3

2d ≤ –11 - 3 .

2d ≤ –14.

On dividing both sides by 2 .

d ≤ –7.

For 3d – 9 > 15.

On adding both sides by 9.

3d > 15 + 9 .

3d > 24 .

On dividing both sides by 3 .

d > 8 .

So, A. d ≤ –7 or d > 8.

Therefore, A. d ≤ –7 or d > 8.

7 0

3 years ago

Find the area of the parallelogram shown below and choose the appropriate result.

Lisa [10]

Answer:

The area of the parallelogram is 0.1875 mile² ⇒ D

Step-by-step explanation:

The formula of the area of a parallelogram is A = b1 × h1 = b2 × h2, where

b1 and b2 are two adjacent sides of it

h1 and h2 are the heights perpendicular to these bases

In the given figure

∵ There is a parallelogram

∵ One of its bases is 0.25 mile

∴ b1 = 0.25 mile

∵ the height of this base is 0.75 mile

∴ h1 = 0.75 mile

→ By using the rule of the area above

∴ The area of the parallelogram = 0.25 × 0.75

∴ The area of the parallelogram = 0.1875 mile²

∴ The area of the parallelogram is 0.1875 mile²

6 0

2 years ago

I need help on answering this question

liubo4ka [24]

Answer:

<h2>The answer is 72°</h2>

Step-by-step explanation:

Since < RQS = < QLK and < RQS = x

< QLK is also x

< QLK and < KLM lie on a straight line

Angles on a straight line add up to 180°

To find x add < QLK and < KLM and equate them to 180°

That's

< QLK + < KLM = 180°

x + x - 36 = 180

2x = 180 - 36

2x = 144

Divide both sides by 2

We have the final answer as

Hope this helps you

7 0

3 years ago