A class has 35 students.in how many different ways can five form a group for an activity
1 answer:
Answer:
324,632 possible combinations
Step-by-step explanation:
We are looking for the amount of combinations of 5 students we can have in a class of 35 students. We write this as 35_C_5. The formula for finding the number of combinations of x objects from a set of y objects is x_C_y = .
Then we have:
35_C_5 =
--- expand
--- simplify
324,632 --- simplify
324,632 possible combinations
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The image of the arrow is missing, so i have attached it.
Answer:
A_t = 69.5 cm²
Step-by-step explanation:
In a second image attached, I have divided the arrow into triangle and rectangle.
From the second image,
A1 is area of triangle while A2 is area of rectangle
Area of triangle is; A1 = ½bh
Our triangle base is given as 9 cm.
To get the height, we will subtract the rectangle height of 8 cm from the total arrow height.
Thus; height of triangle; h = 11 - 8 = 3cm
Thus;
A1 = ½ × 9 × 3
A1 = 13.5 cm²
Formula for area of rectangle is;
A2 = length × breadth
A2 = 8 × 7
A2 = 56 cm²
Thus, total area of arrow is;
A_t = A1 + A2 = 13.5 + 56
A_t = 69.5 cm²
The amount of money, b, is $140.
