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3 years ago

A class has 35 students.in how many different ways can five form a group for an activity

Mathematics

1 answer:

Temka [501]3 years ago

7 0

Answer:

324,632 possible combinations

Step-by-step explanation:

We are looking for the amount of combinations of 5 students we can have in a class of 35 students. We write this as 35_C_5. The formula for finding the number of combinations of x objects from a set of y objects is x_C_y = $\frac{x!}{y!*(x - y)!}$ .

Then we have:

35_C_5 = $\frac{35!}{5!*(30!)}$

$\frac{1.0333148*10 ^40}{120*2.6525286*10^32}$ --- expand

$\frac{1.0333148*10^40}{3.1830343*10^34}$ --- simplify

324,632 --- simplify

324,632 possible combinations

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5(2f+3)+7. please simplify

Sergio [31]

Hi there!

5(2f+3)+7
= 10f+15+7
= 10f+22

Hope this helps!

3 0

3 years ago

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If f(x) = 6x2+2, then what is the slope of f(x) at x = 4?

lesya [120]

6(4)^2 + 2
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3 years ago

You are at a restaurant and the check comes to a total of $63. If you want to leave an 18% tip, how much total money should you

astraxan [27]

Answer:

$$74.3$ <em>is the total amount.</em>

Step-by-step explanation:

The first step in this problem is to figure out how much of a tip was left. To find that out, you need to multiply the percentage by the total of the meal.

$63 * .18 = 11.34$

We know that 11.34 was how much of a tip that was left,

To figure out the total amount that was spent, you would add the total amount and the tip.

$63 + 11.34 = 74.34$

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3 years ago

On a recent Summative Assessment, the mean score for the Algebra 1 class was 72 and the standard deviation was 7. See the normal

Flura [38]

<h3>Answer: 20 </h3>

=====================================================

Reasoning:

The empirical rule says that about 68% of the population is within 1 standard deviation of the mean. This applies to the normal distribution.

The mean in this case is 72 and the standard deviation is 7.

One standard deviation below the mean is 72-7 = 65, while one standard deviation above the center point is 72+7 = 79. This is visually shown as the closest tickmarks to the center 72. Each tickmark represents a unit of standard deviation (eg: 85 is two standard deviations above the mean, since it's 2 tickmarks above 72).

Saying "within 7 points of the mean" therefore is the same as saying "the score is between 65 and 79, inclusive of both endpoints".

So you're teacher is asking how many students got between 65 and 79. As mentioned at the very top, roughly 68% of the population fits this description.

Meaning,

68% of 30 = 0.68*30 = 20.4 = 20 students got a quiz score within seven points of the mean.

5 0

3 years ago

The function f has a domain of {1, 3, 5, 7} and a range of {2, 4, 6}. Could f be represented by {(1, 2), (3, 4), (5, 6), (7, 2)}

bezimeni [28]

Answer:

Yes

Step-by-step explanation:

- Yes, a function with those domain and range values could certainly be represented by those points.

- (1,2) and (7,2) are points with separate domain values but identical range values: this is allowed because every x value is only assigned one y value (remember, one number x in domain cannot have two different numbers y in the range).

- Another way is the use of Vertical Line test of the curve passing through to the points {(1, 2), (3, 4), (5, 6), (7, 2)}. sketch down multiple vertical lines passing through the curve. If any particular vertical line intersects the curve at more than one point on the curve then the curve is not a function of y = f(x).

- You would see that all vertical lines are free this invalidation. Hence, y is a function of x having points {(1, 2), (3, 4), (5, 6), (7, 2)}.

5 0

4 years ago