All categories

4 years ago

What is useful in checking a quotient for long division.

1 answer:

6 0

Hey there! :D

Your answer could be to multiply the quotient by the dividend.

Sorry If I Couldn't Be Much Of A Help!!

Have A Good Friday!! :P

You might be interested in

PLEASEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Snezhnost [94]

The answer is rhombus

7 0

3 years ago

Read 2 more answers

Use matrix addition to solve this equation: B + 15 −7 4 0 1 2 = 1 2 12 4 0 2 b11 = b12 = b13 = b21 = 4 b22 = −1 b23 = 0

Arada [10]

Answer:

$b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0$

Step-by-step explanation:

The given matrix addition is

$B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

We need to find the elements of matrix B.

Let $B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}$

Substitute the value of matrix.

$\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

After addition of two matrix we get

$\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

On equating both sides.

$b_{11}+15=1\Rightarrow b_{11}=-14$

$b_{12}-7=2\Rightarrow b_{12}=9$

$b_{13}+4=12\Rightarrow b_{13}=8$

$b_{21}+0=4\Rightarrow b_{21}=4$

$b_{22}+1=0\Rightarrow b_{22}=-1$

$b_{23}+2=2\Rightarrow b_{23}=0$

Therefore, the elements of matrix B are $b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0$ .

3 0

3 years ago

Factor the trinomial x^2 - 7x + 10

Valentin [98]

Answer:

(x-5) (x-2)

Step-by-step explanation:

x^2 (-2x-5x) +10

basically you will write the equation down and then to double check multiply the x and then the -5 into (x-2). this can be repetitive if you get it wrong so try to do numbers that make sense.

7 0

3 years ago

The function f has first derivative given by f'(x)=(x)^1/2/1+x+x^3. What is the x-coordinate of the inflection point of the grap

Anestetic [448]

Inflection at f'(x) = 0

x^1/2 / (1 + x + x^3) = 0 

The x coordinate is x = 0 

or "C" from your choices there. 

The simplest way is to notice that this happens when x = 0. The reason is you got: 

x^1/2 / (some expression) 

at x = 0 the numerator is 0 so unless the denominator is also 0 the result is 0. 

The denominator for x = 0 is 1 so you get 

0/1 = 0.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

4 0

3 years ago

The weight of a beg of pears at the local market averages 8 pounds with a standard deviation of 0.5 pound. The weight of all the

Blababa [14]

Mean weight of the bag of pears = u = 8 pounds
Standard deviation = s = 0.5 pounds

We have to find what percentage of bags of pears will weigh more than 8.25 pounds. This can be done using the z score.

We have to convert x = 8.25 to z scores, which will be:

$z= \frac{x-u}{s}= \frac{8.25-8}{0.5}$

z score = 0.5

From the z table, the probability of z score being greater than 0.5 is 0.3085

Therefore, the probability of a bag to weigh more than 8.25 pounds is 0.3085

Thus 0.3085 or 31% (rounded to nearest integer) of bags of pears will have weight more than 8.25 pounds at the local market.

4 0

3 years ago