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maw [93]
3 years ago
15

If sin pheta < 0 and tan pheta < 0 then:​

Mathematics
1 answer:
maria [59]3 years ago
5 0

sin(θ) < 0 is another way to say sin(θ) is negative.

tan(θ) < 0 is another way to say tan(θ) is negative.

let's recall that, on the III Quadrant sine and cosine are both negative, and thus the tangent is positive, recall tan(θ)=sin(θ)/cos(θ).

on the IV Quadrant however, sine is negative and cosine is positive, thus tangent is negative.

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16
svlad2 [7]

Answer:

|x - 4| ≤ 0.3

Step-by-step explanation:

The actual width = 4

Maximum variation, x = 0.3

Hence, the lowest width position based on actual width and possible variation is :

4 - 0.3 ≤ x ≤ 4 + 0.3

3.7 ≤ x ≤ 4.3

7 0
3 years ago
19.
vichka [17]

Answer:

168

Step-by-step explanation:

Sum the parts of the ratio, 6 + 7 = 13 parts

Divide the total number of students by 13 to find the value of one part of the ratio.

364 ÷ 13 = 28 ← value of 1 part of the ratio, thus

number of girls = 6 × 28 = 168

3 0
3 years ago
unit 1 chapter 1 gross income answersA portion of Donald Irwin’s time sheet is shown below. Determine the total number of hours
statuscvo [17]

Answer:

i need points

Step-by-step explanation:

7 0
2 years ago
Homework Jim Thompson! PART 2
BlackZzzverrR [31]

Problem 2

Part (a)

The 3D shape formed when rotating around the y axis forms a pencil tip

The shape formed when rotating around the x axis is a truncated cone turned on its side.

------------

Part (b)

Check out the two diagrams below.

============================================================

Problem 3

Answer: Choice A and Choice C

-----------------------

Explanation:

Think of stacks of coins. Let's say we had 2 stacks of 10 quarters each. The quarters are identical, so they must produce identical volumes. Those sub-volumes then add up to the same volume for each stack. Now imagine one stack is perfectly aligned and the other stack is a bit crooked. Has the volume changed for the crooked stack? No, it hasn't. We're still dealing with the same amount of coins and they yield the same volume.

For more information, check out Cavalieri's Principle.

With all that in mind, this leads us to choice C. If the bases are the same, and so are the heights, then we must be dealing with the same volumes.

On the other hand, if one base is wider (while the heights are still equal) then the wider based block is going to have more volume. This leads us to choice A.

6 0
2 years ago
Solve each system of equations 3x + 2y = 26 3x - 2y = 10 Ordered pair
MrMuchimi

Let's solve the following system of equations

\begin{gathered} 3x+2y=26 \\ 3x-2y=10 \end{gathered}

Eq 1 + Eq 2

3x+2y+3x-2y=26+106x=36x=6

Now for y

y=\frac{26-3x}{2}y=\frac{26-3\cdot6}{2}y=\frac{8}{2}y=4

6 0
1 year ago
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