Answer:
B.
The sum of 5 and 3 times the difference of a number and 6
5 + 3 x (X-6)
Hope this helps
Step-by-step explanation:
Answer:
A; 5/36
Step-by-step explanation:
ITS THE ONLY ONE THAT MALES SENSE THERE ARE 36 POSSIBLE OUTCOMES
Question:
Consider the expression
When using the inspection method the number you would add to (and subtract from) the constant term of the numerator so the polynomial in the numerator will have (x + 3) as a factor is?
Answer:
The constant to add is 4
Step-by-step explanation:
Given
First, we need to get an expression that has x + 3 has its factor.
Represent this expression with: ![(x + 3)(x + k)](https://tex.z-dn.net/?f=%28x%20%2B%203%29%28x%20%2B%20k%29)
Expand
![x^2 + 3x + kx + 3k](https://tex.z-dn.net/?f=x%5E2%20%2B%203x%20%2B%20kx%20%2B%203k)
Group like terms
![x^2 + (3 + k)x + 3k](https://tex.z-dn.net/?f=x%5E2%20%2B%20%283%20%2B%20k%29x%20%2B%203k)
Compare the above expression to: ![x^2 + x - 10](https://tex.z-dn.net/?f=x%5E2%20%2B%20x%20-%2010)
![(3 + k)x = x](https://tex.z-dn.net/?f=%283%20%2B%20k%29x%20%3D%20x)
![3k = -10](https://tex.z-dn.net/?f=3k%20%3D%20-10)
However, we only consider solving
for k
![(3 + k)x = x](https://tex.z-dn.net/?f=%283%20%2B%20k%29x%20%3D%20x)
![3 + k = 1](https://tex.z-dn.net/?f=3%20%2B%20k%20%3D%201)
Subtract 3 from both sides
![3 - 3 + k = 1 - 3](https://tex.z-dn.net/?f=3%20-%203%20%2B%20k%20%3D%201%20-%203)
![k = 1 - 3](https://tex.z-dn.net/?f=k%20%3D%201%20-%203)
![k= -2](https://tex.z-dn.net/?f=k%3D%20-2)
Substitute -2 for k in ![(x + 3)(x + k)](https://tex.z-dn.net/?f=%28x%20%2B%203%29%28x%20%2B%20k%29)
![(x + 3)(x + k) = (x + 3)(x -2)](https://tex.z-dn.net/?f=%28x%20%2B%203%29%28x%20%2B%20k%29%20%3D%20%28x%20%2B%203%29%28x%20-2%29)
![(x + 3)(x + k) = x^2 + 3x - 2x - 6](https://tex.z-dn.net/?f=%28x%20%2B%203%29%28x%20%2B%20k%29%20%3D%20x%5E2%20%2B%203x%20-%202x%20-%206)
![(x + 3)(x + k) = x^2 + x - 6](https://tex.z-dn.net/?f=%28x%20%2B%203%29%28x%20%2B%20k%29%20%3D%20x%5E2%20%2B%20x%20-%206)
So, the expression that has a factor of x + 3 is ![x^2 + x - 6](https://tex.z-dn.net/?f=x%5E2%20%2B%20x%20-%206)
To get the constant term to add/subtract, we have:
![Constant = (x^2 + x - 6) - (x^2 + x - 10)](https://tex.z-dn.net/?f=Constant%20%3D%20%28x%5E2%20%2B%20x%20-%206%29%20-%20%28x%5E2%20%2B%20x%20-%2010%29)
Open brackets
![Constant = x^2 + x - 6 - x^2 - x + 10](https://tex.z-dn.net/?f=Constant%20%3D%20x%5E2%20%2B%20x%20-%206%20-%20x%5E2%20-%20x%20%2B%2010)
Collect Like Terms
![Constant = x^2 - x^2+ x - x - 6+ 10](https://tex.z-dn.net/?f=Constant%20%3D%20x%5E2%20-%20x%5E2%2B%20x%20%20%20-%20x%20-%206%2B%2010)
![Constant = - 6+ 10](https://tex.z-dn.net/?f=Constant%20%3D%20%20-%206%2B%2010)
![Constant = 4](https://tex.z-dn.net/?f=Constant%20%3D%20%204)
I think it's 12 if that's an option
Area of a square = side^2
A = 32^2 = 1024 yds^2
I hope this is the answer that you were looking for.