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3 years ago

What is the common number of 5,4,100,1

Mathematics

1 answer:

cestrela7 [59]3 years ago

6 0

Answer:

Step-by-step explanation:

These number can be de composed in primer factors as it is shown:

100=5*5*2*2*1

5=5*1

4=2*2*1

1=1

Where we can see that the only common number is 1

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HELP!!!!!!!!!!!!!!!!!!!!!!!

Agata [3.3K]

Answer:

B would be (-1, -2)

C would be (-1, 1)

A would be (-4, -2)

Step-by-step explanation:

The ordered pairs are affected by the y value. The X value stays the same since you didn't move the shape any to the right or left. The y values went down three on all of the points because you moved the whole shape down three spots.

I hope this helps! Please mark as brainliest! Just ask if you need anymore help! :D Good Luck!

8 0

3 years ago

Latoya drives 8 miles to work in 13 minutes. What is her average rate, in miles per hour, when rounded to the nearest wholes num

Mama L [17]

Answer:

37 miles per hour

Step-by-step explanation:

To find the average rate (average speed) of Latoya in miles per hour, you would divide the distance traveled (in miles) by the time taken to travel (in hours).

So we know that Latoya traveled 8 miles in 13 minutes. We cannot divide 8 by 13, because 13 is in minutes, not hours. We must convert 13 minutes to hours before dividing.

There are 60 minutes in one hour, so to covert minutes into hours, we would divide the minutes (13) by 60. Doing this would give you 13/60. You cannot simplify the fraction 13/60, because 13 is a prime number. It would be best to just leave it as it is for now. So Latoya traveled for 13/60 hours.

Now, to find her average rate in miles per hour, you divide the distance traveled in miles (8 miles) by the time it took to travel in hours (13/60):

8 ÷ 13/60

Remember, a ÷ b/c = a × c/b. Using this:

8 ÷ 13/60 = 8 × 60/13 = 480/13 ≈ 37 rounded to the nearest whole number.

Latoya had an average rate of about 37 miles per hour.

I hope this helps. :)

6 0

2 years ago

Let l be the length of a diagonal of a rectangle whose sides have lengths x and y, and assume that x and y vary with time. If x

meriva

The rate of change of the size of the diagonal is; 25.2 ft/s

By Pythagoras theorem;

The length, l of a diagonal of a rectangle whose sides have lengths x and y is;

l² = x² + y².

In essence; the length of the diagonal is dependent on the length, x and y of the sides.

Therefore;

(dl/dt)² = (dx/dt)² + (dy/dt)²

where;

(dx/dt) = 19 ft/s
(dy/dt) = -15 ft/s

Therefore,

(dl/dt)² = 19² + (-15)²

(dl/dt)² = 361 + 225

dl/dt = √586

dl/dt = 25.2

Therefore, the size of the diagonal is changing at a rate of; 25.2 ft/s.