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Anna [14]
3 years ago
10

Help me out pleaseeeeee

Mathematics
2 answers:
elixir [45]3 years ago
8 0
Is it the first one?
marin [14]3 years ago
7 0

Answer:

A

Step-by-step explanation:

LCM of 5 and 3 is 15

thus, denominator is 15

2/5 = 2x3/5x3 = 6/15

1/3 = 1x5/3x5 = 5/15

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Solve for 43.<br> 43 = [?]<br> 58°<br> 139° 41°<br> 43
Dovator [93]

Answer:

∠3 = 81

Step-by-step explanation:

Interior angles in a triangle add up to equal 180°

Hence, 58° + 41° + ∠3 = 180

58 + 41 = 99

99 + ∠3 = 180

* subtract 99 from each side *

99 - 99 cancels out

180 - 99 = 81

we're left with ∠3 = 81°

4 0
2 years ago
Nicky is considering two different companies for textbook rentals. For
maks197457 [2]

Answer:

if youre answer has to be a whole number it would be 3 otherwise it would be  x<4 ( so anything less than 4 )

Step-by-step explanation:

so because we are trying to find which company is less, we need to set up in inequality.

so first lets do company A

because 15 is our reoccuring fee, its going to be the coeifficient

so the equation would be

A - 15x + 20

now lets do company B

because it only 20 every month we dont need to have a constant which means the equation for B would be

B - 20x

so lets put it all together

15x + 20 > 20x ( remember our B side has to be less )

now lets solve it

20 > 5x

we know that if x = 4 then the two would be equal, which means our answer would have to be 3 months.

now always check your work.

15 (3) + 20 = 65

20(3) = 60

3 0
3 years ago
H(a) = a^2 + 3a; Find h(-10)
Colt1911 [192]
H(-10)=70
because when you input -10 in for each a, it will equal 70
6 0
2 years ago
Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess
Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2

4 0
3 years ago
Read 2 more answers
Find the inverse of the given relation.
Greeley [361]

Answer:

C

Step-by-step explanation:

first look at all the numbers in the relation.then since inverse means opposite find the answers where the numbers in the parenthesis are in the opposite order than the question. Finally look for the answer In which all the positive numbers in the parenthesis(in the given relation) are negative (on the answers)and the negative numbers (in the given relation) are positive (on the answers).

4 0
3 years ago
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