Help me out pleaseeeeee

Right now Seth's age is 4/5 the age of his brother Eric. Twenty-one years ago, Eric was twice as old as Seth. What are their age

lana [24]

Answer:

Present Time

Let X= Eric's age (4/5)X= Seth's age

Question: What are their ages now?________________________________________________________________________

Past (21 years ago)

X-21 =Eric's age (4/5)X-21=Seth's age

2*[4/5(X-21]=Eric's age

Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution

_______________________________________________________________________

X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.

X-21+42=(8/5) X

X+21 = (8/5)X Subtract "X" from both sides.

21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3

21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.

Then find 4/5 (X)= Seth's age

8 0

1 year ago

Read 2 more answers

If each customer takes 3 minutes to check out, what is the probability that it will take more than 9 minutes for all the custome

AnnyKZ [126]

Using a discrete probability distribution, it is found that there is a 0.15 = 15% probability that it will take more than 9 minutes for all the customers currently in line to check out.

<h3>What is the discrete probability distribution?</h3>

Researching the problem on the internet, it is found that the distribution for the number of customers in line at the store is given by:

P(X = 0) = 0.2;

P(X = 1) = 0.15;

P(X = 2) = 0.30;

P(X = 3) = 0.20;

P(X = 4) = 0.10;

P(X = 5) = 0.05;

Hence, since each customer takes 3 minutes to check out, the probability that it will take more than 9 minutes for all the customers currently in line to check out is the probability that there are more than 3 customers, hence:

P(X > 3) = P(X = 4) + P(X = 5) = 0.10 + 0.05 = 0.15.

0.15 = 15% probability that it will take more than 9 minutes for all the customers currently in line to check out.

More can be learned about a discrete probability distribution at brainly.com/question/24855677

7 0

1 year ago

5-4. Solve each of the following equations for the indicated variable. Use your Equation Mat if it is helpful. Write down each o

balu736 [363]

QUESTION 1

The given equation is :

$2(y - 3) = 4$
We want to solve for y. This means we have to isolate y on one side of the equation while all other constants are also on the other side of the equation,

We first divide both sides by 2 to obtain,

$\frac{2(y - 3)}{2} = \frac{4}{2}$

We cancel out the common factors to get,

$y - 3 = 2$

We now group like terms to get,

$y = 3 + 2$

We simplify to obtain,

$y = 5$

QUESTION 2

The given equation is

$2x + 5y = 10$
We want to solve for x. This means that we need to isolate x on one side of the equation, while all other variables and constant are also on the other side of the equation.

This implies that,

$2x= 10 - 5y$

We now divide through by 2, to obtain,

$\frac{2x}{2} = \frac{10}{2} - \frac{5y}{2}$

This will now give us,

$x = 5 - \frac{5}{2} y$

QUESTION 3

The given equation is
$6x + 3y = 4y + 11$

We want to solve for y. This means that we need to isolate y on one side of the equation, while all other variables and constants are also on the other side of the equation.

We first of all group all the y terms on one side of the equation to obtain,

$6x - 11 = 4y - 3y$

We simplify to get,

$6x - 11 = y$

This implies that,

$y = 6x - 11$

QUESTION 4

The given equation is,

$3(2x + 4) = 2 + 6x + 10$

We want to solve for x. This means that we need to isolate x on one side of the equation, while all other variables and constant are also on the other side of the equation.

Let us first expand the brackets to get,

$6x + 12 = 2 + 6x + 10$
This implies that

$6x + 12 = 6x + 12$

We group like terms to get,

$6x - 6x = 12 - 12$

We now simplify both sides to get,

$0x = 0$

We don't want x to vanish, so let us try to divide both sides by zero to get,

$x = \frac{0}{0}$

This is an indeterminate form, which implies that, x has infinitely many solutions. This means that all the real numbers are solution to the equation.

$\therefore \: x \in \: R$

QUESTION 5

The given equation is,

$y = - 3x + 6$

We want to solve for x, so we add the additive inverse of 6, which is -6 to both sides of the equation to get,

$y - 6 = - 3x$

We rewrite this to obtain,

$- 3x = y - 6$

We divide through by -3 to get,

$\frac{ - 3x}{ - 3} = \frac{y}{ - 3} - \frac{6}{ - 3}$

This will give us,

$x = - \frac{y}{3} + 2$

or

$x= 2 - \frac{1}{3} y$

5 0

2 years ago

Mariana averaged 80 on her first three math exams. The first score was 86. The second score was 74. What was the third exam scor

Anna71 [15]

The three scores are 86, 74, and an unknown score x. The average (i.e. the sum divided by how many there are) is 80, so we have

$\dfrac{86+74+x}{3}=80$

Multiply both sides by 3 and you get

$160+x=240$

Subtract 160 from both sides to get

$x=240-160=80$

Note: you could solve this exercise very quickly if you notice that the two numbers, 86 and 74, are symmetrical with respect to 80, which is the average. So, the third number must be the average.

6 0

2 years ago

2<br> Which is a factor of 4x + x - 14

kiruha [24]

Answer: 5x - 14

Step-by-step explanation: Combine like terms 4x + x - 14 and turn it into 5x - 14

4 0

2 years ago