What you have to do is multiply 5.12*2
10.24 meters
Answer:
A=BH so, Area is 108 inches :)
Step-by-step explanation:
A= B x H
A = 12 x 9
A = 108
For this case we have the following equation:
d = 0.5 + 5t
We will describe the equation step by step.
0.5: Initial distance Jillian walked
5: speed with which Jillian begins to jog
t: independent variable that indicates the number of hours
y: dependent variable that indicates the distance traveled in miles
Answer:
The variable variable is time and the dependent variable is distance.
The speed of wind and plane are 105 kmph and 15 kmph respectively.
<u>Solution:</u>
Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.
We have to find the air speed of the plane and speed of the wind.
Now, let the speed wind be "a" and speed of aeroplane be "b"
And, we know that, distance = speed x time.

Now at head wind → 
So, solve (1) and (2) by addition
2a = 210
a = 105
substitute a value in (1) ⇒ 105 + b = 120
⇒ b = 120 – 105 ⇒ b = 15.
Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.
Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.
Answer:
Step-by-step explanation:
0.25=25/100=1/4