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Maru [420]
3 years ago
15

Help plz plzzzz 20 points!!!!

Mathematics
2 answers:
Genrish500 [490]3 years ago
7 0
1: 14 ft
2: 18
3: 11; 28
4: 8; 96
5: a = 5x3
6: a = 8x8
7: 1x42, 2x21, 3x14, and 6x7. 6x7 probably makes the most sense.
ozzi3 years ago
7 0
One is 14 andnsmakisskiskaksjrf
You might be interested in
Which is the best estimate for the percent equivalent to 3/8​
Doss [256]

Answer:

D. 38%

Step-by-step explanation:

3/8 as a percentage is 37.5% and that is rounded to 38%! :) 37% is close but it is not rounded making it not the best estimate, therefore it is not correct.

8 0
3 years ago
In Ms Barclay's classroom 2/5 students play chess. 5/6 of the students play Sudoku. If there are 30 students, in her class how m
Nonamiya [84]

Answer:

12 students play chess

and 25 students play Sudoku

Step-by-step explanation:

There are 30 students in Ms Barclay's classroom.

2/5 students play chess.

i.e. \dfrac{2}{5}\times 30  play chess

i.e. 12 students play chess

5/6 of the students play Sudoku.

i.e. \dfrac{5}{6}\times 30  play Sudoku

i.e. 25 students play Sudoku

Hence, 12 students play chess

and 25 students play Sudoku

6 0
3 years ago
What is x in the equation 753.6=(3.14)(6)^2(x)
vichka [17]

Answer:

 x = 20/3 = 6.667

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "3.14" was replaced by "(314/100)". 2 more similar replacement(s)

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

          (7536/10)-(((314/100))*(6)^2*(x))=0

Step by step solution :

Step  1  :

1.1     6 = 2•3

(6)2 = (2•3)2 = 22 • 32

Equation at the end of step  1  :

 7536      314

 ———— -  ((——— • (22•32)) • x)  = 0

  10       100

Step  2  :

           157

Simplify   ———

           50

Equation at the end of step  2  :

 7536      157

 ———— -  ((——— • (22•32)) • x)  = 0

  10       50

Step  3  :

Dividing exponents :

3.1    22   divided by   21   = 2(2 - 1) = 21 = 2

Equation at the end of step  3  :

 7536     2826

 ———— -  (———— • x)  = 0

  10       25

Step  4  :

           3768

Simplify   ————

            5  

Equation at the end of step  4  :

 3768    2826x

 ———— -  —————  = 0

  5       25  

Step  5  :

Calculating the Least Common Multiple :

5.1    Find the Least Common Multiple

     The left denominator is :       5

     The right denominator is :       25

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

5 1 2 2

Product of all

Prime Factors  5 25 25

     Least Common Multiple:

     25

Calculating Multipliers :

5.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Making Equivalent Fractions :

5.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3768 • 5

  ——————————————————  =   ————————

        L.C.M                25  

  R. Mult. • R. Num.      2826x

  ——————————————————  =   —————

        L.C.M              25  

Adding fractions that have a common denominator :

5.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3768 • 5 - (2826x)     18840 - 2826x

——————————————————  =  —————————————

        25                  25      

Step  6  :

Pulling out like terms :

6.1     Pull out like factors :

  18840 - 2826x  =   -942 • (3x - 20)

Equation at the end of step  6  :

 -942 • (3x - 20)

 ————————————————  = 0

        25      

Step  7  :

When a fraction equals zero :

7.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -942•(3x-20)

 ———————————— • 25 = 0 • 25

      25    

Now, on the left hand side, the  25  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -942  •  (3x-20)  = 0

Equations which are never true :

7.2      Solve :    -942   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

7.3      Solve  :    3x-20 = 0

Add  20  to both sides of the equation :

                     3x = 20

Divide both sides of the equation by 3:

                    x = 20/3 = 6.667

One solution was found :

                  x = 20/3 = 6.667

6 0
4 years ago
Coach kunal stacks all of the tennis balls in a square pyramid. The number of tennis balls, P(n), in n layers of the square pyra
Zolol [24]

Answer:

D. 9

Step-by-step explanation:

We are told in the question that: The number of tennis balls represented by P(n), in n layers of the square pyramid is given as

P(n) = P(n - 1) + n²

Let's take the first layer

n = 1

P(1) = P(1 - 1) + 1²

P(1) = 1 tennis ball.

It is important to note that the first layers we have one tennis ball.

Let's take the second layer

n = 2

P(2) = P(2 - 1) + 2²

P(2) = P(1) + 2²

Note that: P(1) above = 1

P(2) = 1 + 2²

P(2) = 5 tennis balls

It is important to note that the second layer we have five tennis balls

Let's take the third layer

n = 3

P(3) = P(3 - 1) + 3²

P(3) = P(3 - 1) + 3²

P(3) = P(2) + 3²

Note that: P(2) above = 5

P(3) = 5 + 3²

P(3) = 14 tennis balls

It is important to note that the second layer we have fourteen tennis balls

Let's take the fourth layer

n = 4

P(4) = P(4 - 1) + 4²

P(3) = P(4 - 1) + 4²

P(3) = P(3) + 4²

Note that: P(3) above = 14

P(3) = 14 + 4²

P(3) = 30 tennis balls

It is important to note that the fourth layer we have thirty tennis balls

Hence, the number of tennis balls from the first four layers will be: 1, 5, 14, 30,

So, the number of tennis balls that Coach Kunal could not have is 9.

8 0
3 years ago
Timed Test Please Help.
Alinara [238K]

Answer:

6.5 × 10¹¹

Step-by-step explanation:

I hope this helps you

5 0
3 years ago
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