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Maru [420]
3 years ago
15

Help plz plzzzz 20 points!!!!

Mathematics
2 answers:
Genrish500 [490]3 years ago
7 0
1: 14 ft
2: 18
3: 11; 28
4: 8; 96
5: a = 5x3
6: a = 8x8
7: 1x42, 2x21, 3x14, and 6x7. 6x7 probably makes the most sense.
ozzi3 years ago
7 0
One is 14 andnsmakisskiskaksjrf
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12x2 + 3x + 6 and -7x2 - 4x - 2
Semenov [28]

Answer:

Step-by-step explanation:12x2 + 3x + 6 + (-7)x2 - 4x - 2 = 0

12•x•2 + 3•x + 6 + (-7)•x•2 - 4•x - 2 = 0

9x = -4

x = -4/

9

≈ -0.444444

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2 years ago
What decimal is 1/10 of 0.08
Vera_Pavlovna [14]
The answer is 0.008. Hopefully you understand why :)


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3 years ago
According to the box-and-whisker plot shown above, what are the following:
Readme [11.4K]

Answer:

  6.  80

  7.  60

  8.  100

  9.  40

  10.  110

Step-by-step explanation:

A box and whisker plot is a visual representation of the 5-number summary of a data set. The features of the plot are, left-to-right, the minimum, first quartile, median, third quartile, maximum.

You are being asked to identify the numerical value associated with each of these features.

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The left whisker extends to the minimum of 40.

The left end of the box identifies the first quartile as 60.

The line in the middle of the box is the median, 80.

The right end of the box identifies the third quartile as 100.

The right whisker extends to the maximum of 110.

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<em>Additional comment</em>

We hope you can rearrange the order of these numbers to suit the order in which the questions ask for them.

4 0
2 years ago
Mr. Rodriguez used a random sample of 20 students from each grade at Willowbrook School to determine their favorite types of rea
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Answer:

A- Overall, students are less interested in reading magazines than comics.

7 0
3 years ago
Read 2 more answers
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }&#10;\\\\&#10;\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ( h, k)\\&#10;vertices\ ( h,  k\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{ a ^2 + b ^2}\\&#10;asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)&#10;\end{cases}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=2\\&#10;k=-3\\&#10;a=6\\&#10;c=2\sqrt{10}&#10;\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2&#10;\\\\\\&#10;4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2&#10;\\\\\\&#10;\sqrt{4}=b\implies 2=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
2 years ago
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