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Sever21 [200]
2 years ago
10

Completing the square x^2-19x-42=0

Mathematics
2 answers:
Ugo [173]2 years ago
8 0

Answer:

x = 2

x = -21

Step-by-step explanation:

Mrac [35]2 years ago
7 0

Answer:

{x}^{2}  - 19x - 42 = 0 \\  {x}^{2}  + 2x - 21x - 42 = 0 \\ x(x + 2) - 21(x + 2) = 0 \\ (x + 2)(x - 21) = 0 \\  \boxed{x =  - 2} \\  \boxed{x = 21}

<h3>(x+2) and (x-21) is the factors of the x²-19x-42.</h3><h3>Value of x is -2 and 21.</h3>
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Using the law of cosines and sines, the measure of angle B is: 38.4°.

<h3>What is the Law of Cosines and Sines?</h3>

Law of cosines is: c = √[a² + b² ﹣ 2ab(cos C)]

Law of sines is: sin A/a = sin B/b = sin C/c

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brainly.com/question/23720007

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