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2 years ago

How do you solve 2x^2+x=-1?

Mathematics

1 answer:

Olin [163]2 years ago

3 0

Answer:

x = 0.2

Step-by-step explanation:

2x^2+x=-1

4x + x = -1

5x = -1

divide by 5

5x/5 = -1/5

x = 0.2

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nirvana33 [79]

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2 years ago

Distribute 2 (9x^2 + 3).

beks73 [17]

Answer:

18x^2+6

Step-by-step explanation:

2(9x^2+3)

multiply each term in parentheses by 2

2 x 9x^2+2 x 3

calculate product

18x^2+2 x 3

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2 years ago

A skateboarder leaves a 12-foot tall ramp with an initial vertical velocity of 8 feet per sen

taurus [48]

To answer this, we substitute 12 ft to the f(h) in the given equation,
f(h) = -8t² + 8t + 12 = 12

Subtracting 12 from both sides of the equation will give us an answer of,

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1 year ago

Read 2 more answers

What algebraic expression models the word phrase three fewer than the sum of c and d?

Serjik [45]

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3 years ago

Read 2 more answers

A random sample of 100 observations from a quantitative population produced a sample mean of 22.8 and a sample standard deviatio

natima [27]

Answer:

We conclude that the population mean is 24.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 24

Sample mean, $\bar{x}$ = 22.8

Sample size, n = 100

Alpha, α = 0.05

Sample standard deviation, s = 8.3

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 24\\H_A: \mu \neq 24$

We use Two-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{22.8 - 24}{\frac{8.3}{\sqrt{100}} } = -1.44$

We calculate the p-value with the help of standard z table.

P-value = 0.1498

Since the p-value is greater than the significance level, we accept the null hypothesis. The population mean is 24.

Now, $z_{critical} \text{ at 0.05 level of significance } = \pm 1.96$

Since, the z-statistic lies in the acceptance region which is from -1.96 to +1.96, we accept the null hypothesis and conclude that the population mean is 24.

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2 years ago