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Nuetrik [128]
4 years ago
12

Factor 2x^2 +1x -10

Mathematics
1 answer:
garik1379 [7]4 years ago
4 0

Answer:

(2x+5)(x−2)

Step-by-step explanation:

Factor 2x2+1x−10

2x2+x−10

=(2x+5)(x−2)

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At her favorite ice cream store, saga can put up to two toppings on an ice cream cone. if there are 106 different ways she can c
grigory [225]
There are 106 different ways Saga can put 2 toppings on her ice cream, including the choice of no toppings. So Saga has 105 different ways of choosing the 2 toppings.

Let the total number of toppings be x. Saga has to choose 2 toppings, so this is a problem of combinations. Combination of 2 objects from can be written as nC2. There are total 105 ways to choosing the toppings, so we can write:

nC2 = 105 \\  \\ 
 \frac{n!}{2!*(n-2)!} =105 \\  \\ 
 \frac{n(n-1)(n-2)!}{2*(n-2)!}=105 \\  \\ 
n(n-1)=105*2 \\  \\ 
n(n-1)=210 \\  \\ 
n=15

Solving the quadratic equation above we get n=15.

This means 15 different toppings were there at the ice cream store.
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Find each percent of increase or decrease. If necessary, round answers to the nearest tenth.
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To make glowing green paint, blue and yellow paint are mixed in a ratio of 3 to 4. how much blue paint and yellow paint should a
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Step-by-step explanation:

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What is the equivalent fraction for 3,2,6,4 whole number?
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Determine the number of degrees of freedom for the two-sample t test or CI in each of the following situations. (Round your answ
tekilochka [14]

Answer:

a

  df =  24.32

b

 df = 30.10

c

 df = 30.7

d

df = 25.5

Step-by-step explanation:

Generally degree of freedom is mathematically represented as

          df =  \frac{ [\frac{ s^2_i }{m} + \frac{ s^2_j }{n} ]^2 }{ \frac{ [ \frac{s^2_i}{m} ]^2 }{m-1 }  +\frac{ [ \frac{s^2_j}{n} ]^2 }{n-1 }  }

Considering a

         a) m = 12, n = 15, s1 = 4.0, s2 = 6.0

           df =  \frac{ [\frac{ 4^2 }{12} + \frac{ 6^2 }{15} ]^2 }{ \frac{ [ \frac{4^2}{12} ]^2 }{12-1 }  +\frac{ [ \frac{6^2}{15} ]^2 }{15-1 }  }

         df =  24.32

Considering b

       (b) m = 12, n = 21, s1 = 4.0, s2 = 6.0

          df =  \frac{ [\frac{ 4^2 }{12} + \frac{ 6^2 }{21} ]^2 }{ \frac{ [ \frac{4^4}{12} ]^2 }{12-1 }  +\frac{ [ \frac{6^2}{21} ]^2 }{21-1 }  }

        df = 30.10

Considering c

      (c) m = 12, n = 21, s1 = 3.0, s2 = 6.0

           df =  \frac{ [\frac{ 3^2 }{12} + \frac{ 6^2 }{21} ]^2 }{ \frac{ [ \frac{3^4}{12} ]^2 }{12-1 }  +\frac{ [ \frac{6^2}{21} ]^2 }{21-1 }  }

           df = 30.7

Considering c

        (d) m = 10, n = 24, s1 = 4.0, s2 = 6.0

                df =  \frac{ [\frac{ 4^2 }{10} + \frac{ 6^2 }{24} ]^2 }{ \frac{ [ \frac{4^2}{10} ]^2 }{10-1 }  +\frac{ [ \frac{6^2}{24} ]^2 }{24-1 }  }

               df = 25.5

   

3 0
3 years ago
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