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AfilCa [17]
2 years ago
9

Tony sold 150 donuts in the first six hours in the day it was open. Every hour they sold six more donoughts the previous hour ho

w much donuts were sold the first three hours
Mathematics
1 answer:
Flura [38]2 years ago
8 0
We are told donut sales is described by an arithmetic sequence of 6 terms whose sum is 150 and common difference is 6. If we split this sequence into two groups of 3 terms, the sum of the first group will differ from the sum of the second group by
  (number of terms)²×(common difference) = 3²×6 = 54

Then if x represents the number of donuts sold in the first 3 hours, the total number of donuts sold is
  x + (x + 54) = 150
  2x = 150 - 54
  x = 96/2 = 48

The number of donuts sold in the first three hours is 48.
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Choose the correct simplification of x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4t
Umnica [9.8K]

Answer:

<h3>The option A) x^{10}z^7 is correct answer.</h3><h3>The correct simplification for the given expression \frac{x^{12}\times z^{11}}{x^2\times z^4} is x^{10}z^7</h3>

Step-by-step explanation:

Given expression is x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4th power.

The given expression can be written as \frac{x^{12}\times z^{11}}{x^2\times z^4}

<h3>To choose the correct simplification of the given expression :</h3>

Now we have to simplify the given expression as below

\frac{x^{12}\times z^{11}}{x^2\times z^4}

=x^{12}\times z^{11}(x^{-2}\times z^{-4})   ( by using the identity \frac{1}{a^m}=a^{-m} )

=(x^{12}.x^{-2})\times (z^{11}.z^{-4})

=x^{12-2}\times z^{11-4} ( by using the identity a^m.a^n=a^{m+n} )

=x^{10}\times z^7

=x^{10}z^7

∴ \frac{x^{12}\times z^{11}}{x^2\times z^4}=x^{10}z^7

<h3>The correct simplification for the given expression \frac{x^{12}\times z^{11}}{x^2\times z^4} is x^{10}z^7</h3><h3>Hence option A) x^{10}z^7 is correct answer.</h3>

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3 years ago
Is my answer right to this problem ​
VLD [36.1K]
Yes it’s right for this problem
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