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Alex777 [14]
2 years ago
13

27,545 milliliters of gas were added to a car's empty gas tank. If the gas tank's capacity is 56 liters 202 milliliters, how muc

h gas is needed to fill the tank?
Mathematics
1 answer:
IRISSAK [1]2 years ago
5 0

Answer:

56,202 milliliters a.k.a 56.202 liters

Step-by-step explanation:

1 liter is equal to 1,000 milliliters. So that'll mean 56 liters is equal to 56,000 milliliters. Add the 202 milliliters to 56,000 and you have 56,202 milliliters, or 56.202 liters.

Let me know if this is correct or not, it's been a while since I did this.

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Having done poorly on their math final exams in​ June, six students repeat the course in summer​ school, then take another exam
pochemuha

Answer:

Yo yo

Step-by-step explanation:

6 0
3 years ago
The tax on a $80 item is $3.20.<br> Find the tax on a $140 item.<br> What is the tax?
allsm [11]
Tax is 4%

Tax in the $140 item is $5.60
(0.04x140)
7 0
2 years ago
If x is an even number, the function f(x) = 2x − 1 gives an odd number. Identify the set of odd numbers corresponding to this se
Alex787 [66]
X = {0, 2, 4, 6, 8}.

=> f(x) = 2x - 1


x                  f(x) = 2x - 1

0                   2*0 - 1 = - 1

2                   2*2 - 1 = 3

4                   2*4 - 1 = 7

6                   2*6 - 1 = 11

8                   2*8 - 1 = 15

Answer: {-1, 3, 7, 11, 15}
4 0
3 years ago
Which point do the graphs of f and g have in common?
pickupchik [31]

The point that the graphs of f and g have in common are (1,0)

<h3>How to get the points?</h3>

The given functions are:

f(x) = log₂x

and

g(x) = log₁₀x

We know that logarithm of 1 is always zero.

This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1

Therefore the point the graphs of f and g have in common is (1,0).

Learn more about graph on:

brainly.com/question/19040584

#SPJ1

6 0
2 years ago
How to find the average squared distance between the points of the unit disk and the point (1,1)
ddd [48]
The unit disk can be parameterized by the function

\mathbf p(r,\theta)=(r\cos\theta,r\sin\theta)

where 0\le r\le 1 and 0\le\theta\le2\pi. The squared distance between any point in this region (x,y)=(r\cos\theta,r\sin\theta) and the point (1, 1) is

(x-1)^2+(y-1)^2=(r\cos\theta-1)^2+(r\sin\theta-1)^2
=(r^2\cos^2\theta-2r\cos\theta+1)+(r^2\sin^2\theta-2r\sin\theta+1)
=r^2(\cos^2\theta+\sin^2\theta)-2r(\cos\theta-\sin\theta)+2
=r^2-2r(\cos\theta-\sin\theta)+2

The average squared distance is then going to be the ratio of [the sum of all squared distances between every point in the disk and the point (1, 1)] to [the area of the disk], i.e.

\dfrac{\displaystyle\iint_{x^2+y^2
=\dfrac{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}[r^2-2r(\cos\theta-\sin\theta)+2]r\,\mathrm dr\,\mathrm d\theta}{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta}
=\dfrac{\frac{5\pi}2}\pi=\dfrac52
5 0
3 years ago
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