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3 years ago

10

How many real solutions does the system have? y=−3x−1y=x2−3x+4?

1 answer:

777dan777 [17]3 years ago

8 0

Set the equations to equal each other:
x²-3x+4=-3x-1
x²-3x+3x+4=-3x+3x-1
x²+4=-1
x²+4-4=-1-4
x²=-5
√x²=√-5
x=-√5i and x=√5i

There are no real solutions.

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A fireman learned a 36 foot ladder against a building.If he placed the ladder 7 feet from the base of the building,what angle is

andrew11 [14]

Answer:
The angle between the ladder and ground is 78.78°

Explanation:
It is given that the length of the ladder is 36 foot and the distance between the base and the ladder is 7 feet.

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3 years ago

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notka56 [123]

Answer:

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3 years ago

What are the coordinates of the vertex of the function f(x)=x^2+10x−3? (–5, –28) (–5, 28) (5, –28) (5, 28)

polet [3.4K]

Answer:

(-5,-28)

Step-by-step explanation:

Given

$f(x)=x^2+10x - 3$

Required

Find the coordinates of the vertex

Given that the function is a quadratic function;

The general form of a quadratic function is

$f(x)= ax^2+bx +c$

By comparison;

$a = 1\ b = 10\ and\ c = -10$

To calculate the coordinates of the vertex;

we start by calculating the x-coordinate;

$x = \frac{-b}{2a}$

Substitute 10 for b and 1 for a

$x = \frac{-10}{2*1}$

$x = \frac{-10}{2}$

$x = -5$

Substitute $x = -5$ in the given function;

$y=x^2+10x - 3$

$y=(-5)^2+10*-5 - 3$

$y=25-50 - 3$

$y=-28$

<em>Hence, the coordinates of the vertex is (-5,-28)</em>

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4 years ago

Can yall help me out ?

larisa86 [58]

I thinks it’s line 5

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3 years ago

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motikmotik

Answer:

54 :)

Step-by-step explanation:

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3 years ago

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