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butalik [34]
3 years ago
12

A bridge underpass in the shape of an elliptical arch, that is, half of an ellipse, is 40 feet wide and 13 feet high. An eight f

oot wide rectangular truck is to drive (safely) underneath. How high can it be?
Mathematics
1 answer:
Liula [17]3 years ago
7 0

Answer:

the truck should not be higher than 12.934 ft

Step-by-step explanation:

if the bridge underpass is half of an ellipse , then the arch function will be B(x,y) such that

x²/a² + y²/b² = 1  , for x≥0 and y≥0 and y=0 for x≤0

where x= width , y= height

for

a= length of the bridge underpass = 40 ft

b= height of the bridge underpass = 13 ft

x²/(40 ft)² + y²/(13 ft)² = 1

that represents all the points of the arch

the maximum height is reached when the truck touches the arch, then

for a point x= 4 ft wide , since 8 foot wide represents 4 foot to the left (x=-4) and 4 foot to the right (x=4)

then

(4 ft)²/(40 ft)² + y²/(13 ft)² = 1

1/100 - y²/(13 ft)² = 1

y/13 ft =  √(1-1/100) = 3/10*√11

y= 3/10*√11 * 13 ft = 12.934 ft

y=  12.934 ft

then the truck should not be higher than 12.934 ft

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