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tatiyna
2 years ago
9

College alcohol and drug use: In a Washington Post/Kaiser Family Foundation poll conducted from January through March 2015, 56%

of adults (ages 17‐26) who attended college during the past 4 years say that alcohol and drug use at their school is a big problem. The 95% confidence interval is (0.53, 0.59).
Which of the following is an appropriate interpretation of the 95% confidence interval?

A)There is a 95% probability that the proportion of adults (ages 17‐26) who attended college during the past 4 years say that alcohol and drug use at their school is a big problem is between 53% and 59%.
B)We are 95% confident that the proportion of the sample who say that alcohol and drug use at their school is a big problem is between 53% and 59%.
C)Of random samples of the same size, 95% will have between 53% and 59% of respondents who say that alcohol and drug use at their school is a big problem.
D)We are 95% confident that the proportion of adults (ages 17‐26) who attended college during the past 4 years and say that alcohol and drug use at their school is a big problem is between 53% and 59%.

Answer:
D
Mathematics
1 answer:
natima [27]2 years ago
8 0

Answer:

D)We are 95% confident that the proportion of adults (ages 17‐26) who attended college during the past 4 years and say that alcohol and drug use at their school is a big problem is between 53% and 59%.

Step-by-step explanation:

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

In this question:

95% confidence interval is (0.53, 0.59).

This means that we are 95% sure that the true proportion for the population of adults who attended college who say that alcohol is a big problem is between 0.53 and 0.59. This means that the answer is given by option D.

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Answer:

See explanation below

Step-by-step explanation:

Find the value of x in each of the following

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5√x-1 = -x -2

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25(x-1) = (-x-2)^2

25(x-1) = x^2+4x + 4

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x^2 +4x + 4 - 25x + 25 = 0

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6 0
2 years ago
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 10 Allen's hummingb
ruslelena [56]

Answer: provided in the explanation segment

Step-by-step explanation:

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⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;

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= 3.15 ± 0.1295 = 3.0205 or 3.2795

(b). normal distribution of weight (c) б is known

(c). option (a) and (e) are correct

(d).  from the question, let sample size be given as S

this gives';

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√S = (1.28 * 0.32) / 0.15 = 2.73

S = 7.4529

cheers i hope this helps

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2 years ago
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