The square will have area
.. (9 cm)^2 = 81 cm^2.
The two triangles together will have area
.. (9 cm)*(12 cm) = 108 cm^2.
The sum of the areas of those three shapes is
.. 81 cm^2 +108 cm^2 = 189 cm^2
Answer: (y^2-a)(1+x-b)
Step-by-step explanation:
Factor out the common terms: =x(y^2-a)-by^2+ab+y^2-a
Then rewrite as: =(y^2-a)x-by^2+ab+1 x (y^2-a)
Factor out the common term (y^2 - a): =(y^2-a)(x+1)-by^2+ab
Factor out the common term b: =(y^2-a)(1+x)+b(-y^2+a)
Rewrite as: =(y^2-a)(1+x)-(y^2-a)b
Factor out the common term (y^2 - a): =(y^2-a)(1+x-b)
Area = length times width i think you got it from there
Answer:
D. (0, 0), (0,3), (-3, 3), (-3, 0).
Step-by-step explanation:
From the statement we know that the vertices of the triangle are:
(0,0) , (0, 3) , (3, 3) , (3, 0).
By multiplying the vertex matrix with the reflection matrix
we create a reflection image in the y-axis.
So the result is letter D. (0, 0), (0,3), (-3, 3), (-3, 0).