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Paraphin [41]
3 years ago
10

fran swims at a speed of 2.4 mph in still water, the river flows at a speed of 0.6mp, how long will it take fran to swim 2.7mi u

pstream? and 2.7mi downstream?  NEED HELP!!
Mathematics
1 answer:
Rainbow [258]3 years ago
5 0
Upstream her speed of 2.4 is decreased by 0.6 to 1.8mph. 2.7mph/1.8m = 1.5 hours
downstream her speed is incresed to 3 mph. 2.7/3 = 0.9 hours
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Stacy uses a spinner with six equal sections numbered 2, 2, 3, 4, 5, and 6 to play a game. Stacy spins the pointer 120 times and
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Answer:

The solution is given below;

Step-by-step explanation:

The computation is shown below:

There is six equal sections are numbered i.e. 2, 2, 3, 4, 5, and 6.

And, Number of Outcome of 2 on the Spinner is 2

Also, total Number of Sections is 6

As the winning spin is a 2

So, The theoretical probability of winning

= 2 ÷6 × 100

= 33.33%

Now

There is a total no of trials be 120

And, the number of outcome of 2 be 30

So, the experimental probability is 30 ÷ 120 = 1 ÷ 4 × 100 = 25%

As 33.3%>25%, this represent that the theoretical probability of winning would be greater.

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A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measurin
Ratling [72]

Answer:

The standard deviation of weight for this species of cockroaches is 4.62.

Step-by-step explanation:

Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

To find : What is the approximate standard deviation of weight for this species of cockroaches?

Solution :

We have given,

Mean \mu=50

The sample mean x=55

A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

i.e. P(X>55)=14%=0.14

The total probability needs to sum up to 1,

P(X\leq 55)=1-P(X>55)

P(X\leq 55)=1-0.14

P(X\leq 55)=0.86

The z-score value of 0.86 using z-score table is z=1.08.

Applying z-score formula,

z=\frac{x-\mu}{\sigma}

Where, \sigma is standard deviation

Substitute the values,

z=\frac{x-\mu}{\sigma}

1.08=\frac{55-50}{\sigma}

1.08=\frac{5}{\sigma}

\sigma=\frac{5}{1.08}

\sigma=4.62

The standard deviation of weight for this species of cockroaches is 4.62.

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