1*3/5 = 3/5.
3/5(t-6) = -0.4
Distribute 3/5
3/5t - 3.6 = -0.4
Add 3.6
3/5t = 3.2
Divide by 3/5
t = 5 1/3 or 5.33
Answer:
Option D.
Step-by-step explanation:
Let the coordinates of a point which divides the segment XY in the ratio of m : n is (x, y).
Segment X(-4, -9) and Y(4, 7) has been divided in the ratio of 2 : 6.
Therefore, x = ![\frac{[4m+n(-4)]}{m+n}=\frac{8-24}{2+6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B4m%2Bn%28-4%29%5D%7D%7Bm%2Bn%7D%3D%5Cfrac%7B8-24%7D%7B2%2B6%7D)
= -
= -2
and y = ![\frac{[7m+n(-9)]}{m+n}=\frac{14-54}{2+6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B7m%2Bn%28-9%29%5D%7D%7Bm%2Bn%7D%3D%5Cfrac%7B14-54%7D%7B2%2B6%7D)
= 
= -5
Therefore, the point (x, y) is (-2, -5).
Option D. will be the answer.
Answer:
yeah it is smaller
one has .16 and the other has .6 and if u take out the six from the 16 then it would be 32.1 and 32.6
Step-by-step explanation:
False
make sure to mark brainliest
Answer:
The 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is between (0.104, 0.224).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is between (0.104, 0.224).