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eimsori [14]
3 years ago
13

Suppose you toss a coin 100 times and get 69 heads and 31 tails. based on these​ results, what is the probability that the next

flip results in a tail​?
Mathematics
1 answer:
Rama09 [41]3 years ago
5 0
The probability would be 31/100.
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Please explain and show work
Vinvika [58]
1*3/5 = 3/5.
3/5(t-6) = -0.4
Distribute 3/5
3/5t - 3.6 = -0.4
Add 3.6 
3/5t = 3.2
Divide by 3/5 
t = 5 1/3 or 5.33
6 0
3 years ago
Read 2 more answers
Find the coordinates of a point that divides the directed line segment XY in the ratio 2:6. answers: A) (3, 5) B) (–1, –3) C) (0
Stells [14]

Answer:

Option D.

Step-by-step explanation:

Let the coordinates of a point which divides the segment XY in the ratio of m : n is (x, y).

Segment X(-4, -9) and Y(4, 7) has been divided in the ratio of 2 : 6.

Therefore, x = \frac{[4m+n(-4)]}{m+n}=\frac{8-24}{2+6}

                    = -\frac{16}{8}

                    = -2

and y = \frac{[7m+n(-9)]}{m+n}=\frac{14-54}{2+6}

         = -\frac{40}{8}

         = -5

Therefore, the point (x, y) is (-2, -5).

Option D. will be the answer.

4 0
3 years ago
Is 32.16 smaller than 32.6
mafiozo [28]

Answer:

yeah it is smaller

one has .16 and the other has .6 and if u take out the six from the 16 then it would be 32.1 and 32.6


6 0
3 years ago
Read 2 more answers
Please help I have 15 minutes!!!!!!
d1i1m1o1n [39]

Step-by-step explanation:

False

make sure to mark brainliest

8 0
3 years ago
Read 2 more answers
stat crunch A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least o
Masteriza [31]

Answer:

The 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is between (0.104, 0.224).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 250, \pi = \frac{41}{250} = 0.164

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.164 - 2.575\sqrt{\frac{0.164*0.836}{250}} = 0.104

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.164 + 2.575\sqrt{\frac{0.164*0.836}{250}} = 0.224

The 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is between (0.104, 0.224).

5 0
3 years ago
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