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lesya692 [45]
3 years ago
9

This is a standard deviation contest. Which of the following sets of four numbers has

Mathematics
2 answers:
Tanya [424]3 years ago
5 0

Answer:

the answer is 0

Step-by-step explanation:

koban [17]3 years ago
4 0
B. The standard deviation is 0
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The sales tax rate is 9 1/2%. Estimate the tax on a $9.98 purchase. How did you arrive at your answer?
stepladder [879]
$9.98 * 1.095 = (that is tax; for ex. if it was 23.6 percent tax it would be 1.236)

<u><em>$10.93</em></u>

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3 years ago
3. A toy car is traveling with a velocity of 4 m/s and has a mass of 1120g. What is the car's
adell [148]
Kinetic Energy
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5 0
3 years ago
Please help me graph the point (7 ,4).
bija089 [108]

Answer:

See explanation

Step-by-step explanation:

From the attachment, the question has been answered. However, the explanation is as follows;

Given that

(x,y) = (7,4)

This means that

x = 7

y = 4

See attachment (1)

Step 1: Locate point 7 on the x axis

Step 2: Locate point 4 on the y axis

Trace these two points until they intersect.

The point at which they intersect, is the required point (7,4) --See attachment (2)

5 0
3 years ago
PLS HELP MEE ASAP 1 MIN LEFT HELPP!!!!!!!!!
artcher [175]

Answer: BC = 5.83

Step-by-step explanation:

Luckily, the triangle is placed on the graph nicely so we can count the legs of the triangle:

AB = 5

AC = 3

BC = ?

To find BC, we can simply use the Pythagorean Theorem:

a^{2}+b^{2}=c^{2}

5^2 + 3^2 = c^2

25 + 9 = c^2

34 = c^2

Now square root to find c, or BC.

\sqrt{34}=\sqrt{c^{2} }

c = 5.83 (rounded by nearest hundredth)

4 0
3 years ago
A man travels 20 km by car from Town P to Town Q at an average speed of x km/h. He finds that the time of the journey would be s
yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2}  = \frac{1 \pm 9 }{-0.4}

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0
2 years ago
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