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madreJ [45]
3 years ago
5

If ABC and GEF are congruent by the ASA criterion, which pair of angles must be congruent

Mathematics
2 answers:
Aleks04 [339]3 years ago
4 0
The second one is true
liq [111]3 years ago
4 0

Answer with explanation:

It is given that,

 ΔABC ≅ ΔG E F--------------[A S A]

→→When two triangles are congruent , corresponding angles as well as Corresponding Sides, are equal.

→≡Corresponding Sides

1. AB=GE

2. BC=E F

3. AC=G F

→≡Corresponding Angles

1. ∠A=∠G

2. ∠B=∠E

3. ∠C=∠F

Option C: →∠CAB=∠E G F

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<img src="https://tex.z-dn.net/?f=solve%20for%20%22m%22%20t%3D%5Cfrac%7Bms%7D%7Bm%2Bn%7D" id="TexFormula1" title="solve for &quo
dalvyx [7]

Answer:

\boxed{\sf \ \ \ m = -\dfrac{tn}{t-s} \ \ \ }

Step-by-step explanation:

Hello,

let s assume that m+n is different from 0

we have this equation and we need to find m as a function of t, s, and n

t=\dfrac{ms}{m+n}

<=>

(m+n)*t=ms\\\\ tm+tn=sm\\ (t-s)m = -tn\\ m = -\dfrac{tn}{t-s}

for t-s different from 0, so t different from s

hope this helps

4 0
3 years ago
M is the midpoint of QR<br><br> M = (-2,6)<br> Q= (8,-10)<br> R = ????
Zolol [24]

Answer:

R = (-12, 22)

Step-by-step explanation:

Unfortunately it's not a straight line, so gonna need to put in some extra work. Basically think of it like breaking it into it's horizontal and vertical components then doubling them.

From Q to M you move 10 spaces to the left, so to go from M to R you will go another 10 to the left.  Similarly, you start at -10 for the y value and go up 16 to 6, and you  will need to go up another 16 to get to R.

So for x, 8 -10 = -2 then -2 - 10 = -12, so R's x value is -12

y we do the same thing.  Gonna do it in one step though.  -10 + 16 + 16 = 22

So R is (-12, 22)

4 0
3 years ago
Simplify using trigonometric identities<br> 2sinθ - sin2θ cosθ
Anit [1.1K]

Double angle identity for sine:

\sin(2x) = 2 \sin(x) \cos(x)

\implies 2 \sin(\theta) - \sin(2\theta) \cos(\theta) = 2 \sin(\theta) - 2 \sin(\theta) \cos^2(\theta)

Factorize the left side.

2 \sin(\theta) - 2 \sin(\theta) \cos^2(\theta) = 2 \sin(\theta) \left(1 - \cos^2(\theta)\right)

Pythagorean identity:

\cos^2(x) + \sin^2(x) = 1

\implies 2 \sin(\theta) \left(1 - \cos^2(\theta)\right) = 2 \sin^3(\theta)

so that

\boxed{2 \sin(\theta) - \sin(2\theta) \cos(\theta) = 2 \sin^3(\theta)}

8 0
1 year ago
A greater number than -8​
sertanlavr [38]
Practically anything above -8
Such as -7, 2, 15600, anything not under -7.9
6 0
2 years ago
This equation shows how the total number of quizzes Angie has ever taken in high school depends on the number of weeks she has a
zepelin [54]

Answer:

9 weeks

Step-by-step explanation:

Knowing that the "q" is the total number of quizzes, you can set the equation equal to 12, and solve for w.

12 = w + 3     Subtract 3 both sides

9 = w

7 0
3 years ago
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