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3 years ago

13

Why do you think it's important that we always label our units on word problems

1 answer:

MAXImum [283]3 years ago

5 0

Word problems describe a situation where something mathematical can be found out about a system. Often, it's a real-world measurement (like numbers of apples, ages of people, inches, feet, etc.) and usually have more than one object being discussed.
The answer must be expressed in specific units so the value cannot be confused with other measurements discussed in the problem.

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The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and

krok68 [10]

Answer:

width is 2 1/4 length 5 5/12

Step-by-step explanation:

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3 years ago

Pls help me I give pick BRAINLIEST!!

mariarad [96]

Answer:

24

Step-by-step explanation:

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2 years ago

Find the variance of the given data rounded to the nearest hundredth 3,4,5,7,10,12,15

True [87]

Answer:

(3 + 4 + 5 + 7 + 10 + 12 + 15)/7 = 8

(3^2 + 4^2 + 5^2 + 7^2 + 10^2 + 12^2 + 15^2)/7 - 8^2 = 17.14285714

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3 years ago

What is the quotient of (4x2 − 27x + 18) ÷ (x − 6)?

zmey [24]

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3 years ago

On Sundays, cars arrive at Sami Schmitt's Scrub and Shine Car Wash at the rate of 8 cars per twenty minute interval. Using the P

Sliva [168]

Answer:

The probability that five cars will arrive during the next thirty minute interval is 0.0127.

Step-by-step explanation:

Let <em>X</em> = number of cars arriving at Sami Schmitt's Scrub and Shine Car Wash.

The average number of cars arriving in 20 minutes is, 8.

The average number of cars arriving in 1 minute is, $\frac{8}{20}=\frac{2}{5}$ .

The average number of cars arriving in 30 minutes is, $\frac{2}{5}\times 30=12$ .

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 12.

The probability mass function of <em>X</em> is:

$P(X=x)=\frac{e^{-12}12^{x}}{x!};\ x=0,1,2,3...$

Compute the probability that 5 cars will arrive in 30 minutes as follows:

$P(X=5)=\frac{e^{-12}12^{5}}{5!}$

$=\frac{6.1442\times10^{-6}\times 48832}{120}$

$=0.0127$

Thus, the probability that five cars will arrive during the next thirty minute interval is 0.0127.

6 0

3 years ago