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azamat
4 years ago
5

Complete the equation below to show a way to write 5/38 as a fraction

Mathematics
1 answer:
vaieri [72.5K]4 years ago
6 0
5/38 is 0.13 because you have to divide them
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Need help with 34,35,36,37
nirvana33 [79]
34. x - 3 = 8x + 4
      -3 - 4 = 8x - x
      -7 = 7x
      -7/7 = x
      -1 = x

y = x - 3
y = -1 - 3
y = -4

solution is (-1,-4)
===================
35. -6 = -x - 2y
      x = -2y + 6

2 + 5x = -2y
2 + 5(-2y + 6) = -2y
2 - 10y + 30 = -2y
32 = -2y + 10y
32 = 8y
32/8 = y
4 = y

2 + 5x = -2y
2 + 5x = -2(4)
2 + 5x = -8
5x = -8 - 2
5x = -10
x = -10/5
x = -2

solution is (-2,4)
==================
36. 4x + 6y = 2000
       x + y = 410
==================
37. 4x + 6y = 2000
       x + y = 410......multiply by -6
----------------------
4x + 6y = 2000
-6x - 6y = - 2460 (result of multiplying by -6)
--------------------add
-2x = - 460
x = -460/-2
x = 230 <=== tickets in advance
 

3 0
3 years ago
What is the value of the constant in the equation that relates the height and
VashaNatasha [74]

Answer:

10 over=5

i asked this quetion

7 0
3 years ago
Read 2 more answers
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
3 years ago
Does the graph represent a function?
Marrrta [24]

Answer:

No, it doesn't pass the vertical line test.

5 0
2 years ago
One year after graduating from college, Sam earned $42,000. Each year, he earned $4000 more.
xxMikexx [17]
The answer is:
an=4000n+38,000

Sam has $42,000 one year after graduating. So when he graduates, he would have $38000.

Hope this helps!

4 0
4 years ago
Read 2 more answers
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