Answer:
It'll take 7.5967 years to have $300 on that account.
Step-by-step explanation:
This problem involves a compounded interest compounded continuously, so in order to solve it we must use the formula for those cases as shown below:
M = C*e^(i*t)
Where M is the final value, C is the initial capital, i is the interest rate and t is the total time. We have:
300 = 250*e^(0.024*t)
e^(0.024*t) = 300/250
e^(0.024*t) = 1.2
0.024*t = ln(1.2)
t = ln(1.2)/0.024 = 7.5967
It'll take 7.5967 years to have $300 on that account.
The terms in which value of x when substituted leaves final value of p(x) = "0".
Here, x - 2 is factor. So value of x is 2.
Substituting value of x we get,
p(x) = x3 - 3x + 5a
p(2) = 2*3 - 3(2) + 5a
0+ 8-6 + 5a
-2 = 5a
a= -0.4
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The y intercept is the point where x = 0 on the line.
When x = 0, y will equal 5.
y - intercept = (0,5)
