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stepladder [879]
3 years ago
11

Area of triangles and quadrilaterals

Mathematics
1 answer:
pishuonlain [190]3 years ago
5 0
Formulas needed:

Square area = b^2
Rectangle area = bh
Triangle area = bh/2
Parallelogram = bh
Trapezoid area = a+b/2(h)
Rhombus area = pq/2

Even better; use online calculators.
To use these formulas, you need to substitute the values given for b,h,a,b,p or/and q and then solve to get area.

So for this example, since it's a rectangle, you use formula A = bh. Base is 5.1, and height is 6.

Substitute now.

A = bh
   = (5.1)(6)  (substitute)
   = 30.6       (multiply)

Therefore the area is 30.6 m^2. Don't forget the unit measurements, which is *measurement*^2.
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ST | PR. Find QR. 35 28 40
Greeley [361]

Answer:

The answer is 47

Step-by-step explanation:

I'm pretty sure this is the answer :)

40 - 28 = 12

35 + 12 = 47

Proof: 35 - 28 = 7

          47 - 40 = 7

8 0
2 years ago
I really need help, someone please help me
Hoochie [10]

Answer:

18.84 meters.

Step-by-step explanation:

The formula for a circle is πr^2.

πr^2 = 28.26

3.14 * r^2 = 28.26

r^2 = 9

r = plus or minus 3.

But since this deals with the area of a circle, there is no way a radius can be negative. So, the radius is 3 meters.

The formula for the circumference is 2πr.

2 * 3.14 * 3 = 6 * 3.14 = 18.84.

So, the circumference of the circle is 18.84 meters.

Hope this helps!

3 0
3 years ago
What is the value of the expression shown below?
statuscvo [17]
The general and correct rule in order of operations is PEMDAS which is parentheses, exponents, multiplication, division, addition then subtraction.

Given the expression <span>2 + (3 + 5)2 ÷ 4 ⋅(1/2)^4
P : </span><span>2 + (8)2 ÷ 4 ⋅(1/2)^4
E : </span><span>2 + (8)2 ÷ 4 ⋅ 0.0625
M: </span><span>2 + 16 ÷ 0.25
D: 2 + 64
A: 66
S: - 

The final answer is then 66.</span>
7 0
2 years ago
Approximate the value of square root of 110 to the nearest hundred
S_A_V [24]
10.49 i belive is the answer
8 0
3 years ago
Read 2 more answers
Landon and Keira what to make enough salsa to build two of the bowls they bought. One bowl holds three pints and the other bowl
tresset_1 [31]
Your answer is 72 ounces

Problem: How many gallons were in the bowls at the start?
less the 34 cups they served during the first intermissionplus the amount the sixth-graders added, made after the first intermission (during the second act)less the quantity served during the second intermission

The result is the 2 gallons of punch at the end of the performance.

To find out how many gallons they had to begin with, work backward, starting with the 2 gallons left at the end of the performance. When working backward, reverse the operations that occurred in the story from beginning to end. Do this by following the steps below.

5 0
3 years ago
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