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nikitadnepr [17]
3 years ago
8

A dartboard consists of a circle inscribed in a square. The area of the circle is 25π square units. The area of the square is 10

0 square units.
Megan randomly throws a dart at the square. Assuming the dart lands within the square, what is the probability that the dart lands within the dartboard? Round your answer to the nearest tenth of a percent.

____%

Mathematics
2 answers:
Aliun [14]3 years ago
8 0
Yeee the answer is 78.5% :)
sammy [17]3 years ago
6 0

Answer::

A dartboard consists of a circle inscribed in a square.

The area of the circle  =  25π square units.

The area of the square = 100 square units.

It is also given that:

Megan randomly throws a dart at the square.

Assuming the dart lands within the square.

We have to find the probability that the dart lands within the dartboard.

⇒ \text{Probability that the dart lands within the dartboard} = \frac{25 \pi}{100} \times 100

Use \pi = 3.14

⇒\text{Probability that the dart lands within the dartboard} = 25 \pi = 25 \times 3.14 = 78.5 \%

Therefore, the probability that the dart lands within the dartboard  to the nearest tenth of a percent is, 78.5 %

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Answer:

A.0.4477

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 16.3, \sigma = 4.2

What is the probability that a randomly selected exam will require between 14 and 19 minutes to​ grade?

This probability is the pvalue of Z when X = 19 subtracted by the pvalue of Z when X = 14. So

X = 19

Z = \frac{X - \mu}{\sigma}

Z = \frac{19 - 16.3}{4.2}

Z = 0.64

Z = 0.64 has a pvalue of 0.7389.

X = 14

Z = \frac{X - \mu}{\sigma}

Z = \frac{14 - 16.3}{4.2}

Z = -0.55

Z = -0.55 has a pvalue of 0.2912

0.7389 - 0.2912 = 0.4477

So the correct answer is:

A.0.4477

7 0
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ad-work [718]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given:

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Solution:

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