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ratelena [41]
2 years ago
11

What is the answer to this problem? (6*6*6)+5*(8+ 1/5)

Mathematics
2 answers:
Rudik [331]2 years ago
7 0
257, as (6 times 6 times 6 is 216), and 5 times of 8 1/5 is 41. Add 41 and 216 and you get 257.
Georgia [21]2 years ago
4 0
Excellent, so first we'll start with the parentheses.
Step 1: (6*6*6) + 5*(8+1/5) rewrite the problem
Step 2: (216) + 5*(41/5) 
Step 3: 216 + 205/5 distribute
Step 4: 216 + 41 divide
Step 5: 257 add
Hope this helps :)
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in the diagram, a building casts a 35-ft shadow and a flagpole casts a 10-ft shadow. if the flagpole is 22tall, how tall is the
8_murik_8 [283]

Let, the height of the building be x ft.

Given the building casts 35ft shadow.

The height of the flagpole given which is 22ft and casts a shadow of 10ft.

Now to find the height of the building we have to equate the ratio of height and shadow of the building and the flagpole.

So we can write,

x/35 = 22/10

To find x, we have to get rid of 35 from the left side and have to move it to right side. As 35 is divided there, we will multiply 35 to both sides.

(x/35)× 35 = (22/10)×35

x = (22×35)/10

x = 770/10

x = 77

So, the height of the building is 77 ft which is the required answer here.

8 0
3 years ago
Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx
uranmaximum [27]
Given the differential equation

5t^3 \frac{dx}{dt} +2x-2=0

The solution is as follows:

5t^3 \frac{dx}{dt} +2x-2=0 \\  \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\  \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\  \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\  \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\  \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\  \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\  \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\  \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1
3 0
3 years ago
Help me plssss!!!!!!!
Nookie1986 [14]
<h3> zor bir soru cevap Ceyhan</h3>

5 0
3 years ago
Marci measured an angle in the intersection of two walkways in a city park as 115°. What is the value of s?
Aleksandr-060686 [28]

Answer:

the answer is D

Step-by-step explanation:

180-115 = 65

7 0
3 years ago
Read 2 more answers
The midpoint of KL is M (-8,1). One endpoint is K (-6,5) find the coordinates of the other endpoint L
PSYCHO15rus [73]

Answer:

Midpoint (x , y) of two points is

( x1 + y1/2 , x2 + y2/2)

Midpoint of KL is M ( -8 , 1)

Let the coordinates of L be ( a , b)

From the above definition

Midpoint between K(-6 , 5) and

L ( a ,b) is

(-8 , 1) = ( -6+a/2 , 5+b/2)

Comparing first point with - 8

- 8 = -6 + a /2

Multiply through by 2

We get

-16 = - 6 + a

a = -16+6

a = - 10

Comparing the second point with 1

1 = 5+b/2

Multiply through by 2

2 = 5 + b

b = 2 - 5

b = -3

Therefore a = -10 and b = - 3

Hence the coordinates of

L is ( -10 , - 3)

Hope this helps

3 0
3 years ago
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