Answer:
pigs
Explanation:
Influenza is an infectious disease caused by influenza viruses, which can be divided into four types A, B, C and D. In humans, influenza A and B viruses are known to cause epidemics, while A viruses are known to cause pandemics. Influenza viruses are also found in birds and mammals (e.g., dogs, cats, cattle pigs and horses). Cross-species virus transmission refers to the transmission process of infectious viruses between hosts from different species. Several viruses that may cause severe diseases in humans have originated from animal species, e.g., avian influenza A virus that can be transmitted to humans through an intermediate host (e.g., pigs). Other examples of cross-species virus transmission include the Ebola virus and Hantaviruses. It has been suggested that cross-species transmission is a common phenomenon in rapidly evolving viruses.
Seminiferous tubles is the only part of a male reproductive system
<h2>Sequence code </h2>
Explanation:
DNA template (non coding strand) is always synthesized from 3'-5' direction and the complementary strand (coding strand) will be synthesized from 5'-3' direction; mRNA synthesized will be from 5'-3' direction and will have the same sequence as coding strand(only in place of T, U will be present)
Sequence 1: 3' TACGCTACGATCGTA 5'
Coding strand 1 : 5' ATGCGATGCTAGCAT 3'
mRNA 1: 5' AUGCGAUGCUAGCAU 3'
AUG codes for methionine(Met); CGA codes for alanine(Ala); UGC codes for threonine(Thr); UAG codes for isoleucine(Iso); CAU codes for valine(Val)
so protein 1 will be:
Met-Ala-Thr-Iso-Val
Sequence 2: 3' TACGCTACTATCGTA 5'
Coding strand 2: 5' ATGCGATGATAGCAT 3'
mRNA 2; 5' AUGCGAUGAUAGCAU 3'
AUG codes for methionine(Met); CGA codes for alanine(Ala); UGA codes for threonine(Thr); UAG codes for isoleucine(Iso); CAU codes for valine(Val)
so protein 2 will be:
Met-Ala-Thr-Iso-Val
Both the protein sequence comes out to be same hence function of protein 2 will be same as that of protein 1
Allele frequency is determined by looking at the dominant and recessive allele of a genotype.
Using the given, we can come up with the following computation for the allele frequency:
allele A = 100/300 allele B = 50/300 allele O = 150/300
Hence, the frequency of allele A is 0.33 or 33%, allele B is .17 or 17% and allele O is 0.50 or 50%.
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