9+8= with line across equal sign 12+=?

Evaluate the surface integral. ??s (x2 y2 z2 ds s is the part of the cylinder x2 y2 = 4 that lies between the planes z = 0 and z

kondor19780726 [428]

The surface $S$ can be parameterized by

$\mathbf r(\theta,z)=(2\cos\theta,2\sin\theta,z)$

where $0\le\theta\le2\pi$ and $0\le z\le2$ . Then the surface integral can be computed with

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS$
$\displaystyle=\int_{\theta=0}^{\theta=2\pi}\int_{z=0}^{z=2}(4\cos^2\theta+4\sin^2\theta+z^2)\|\mathbf r_\theta\times\mathbf r_z\|\,\mathrm dz\,\mathrm d\theta=\dfrac{128\pi}3$

6 0

3 years ago

60 points and brainlyiest!! Hurry

sergiy2304 [10]

Dude it’s. 5 points

6 0

3 years ago

Read 2 more answers

A relay microchip in a telecommunications satellite has a life expectancy that follows a normal distribution with a mean of 93 m

aliina [53]

The insurance period must be chosen so that the probability of a microchip failure within that period is 4%. Reference to a standard normal distribution table shows that the z-score for a cumulative probability of 4% is -1.75.
Let the insurance period be X months:
-1.75 = (X - 93)/3.8
-6.65 = X - 93
X = 83.35 months.
The answer is 83.35 months.

4 0

3 years ago

Tanya has a garden with a trench around it. The garden is a rectangle with width 2 1/2 m and length 2 m. The trench and garden t

vichka [17]

Answer:

The area of a trench is 5.5 m² .

Step-by-step explanation:

Formula

Area of a rectangle = Length × Breadth

As given

Tanya has a garden with a trench around it.

$The\ garden\ is\ a\ rectangle\ with\ width\ 2\frac{1}{2}\ m\ and\ length\ 2\ m.$

i.e

$The\ garden\ is\ a\ rectangle\ with\ width\ \frac{5}{2}\ m\ and\ length\ 2\ m.$

Put in the above formula

$Area\ of\ garden = \frac{5\times 2}{2}$

= 5 m²

As given

$The\ trench\ and\ garden\ together\ make\ a\ rectangle\ with\ width\ 3 \frac{1}{2}\ m\ and\ length\ 3 m.$

i.e

$The\ trench\ and\ garden\ together\ make\ a\ rectangle\ with\ width\ \frac{7}{2}\ m\ and\ length\ 3 m.$

$Area\ of\ garden\ with\ trench = \frac{7\times 3}{2}$

$Area\ of\ garden\ with\ trench = \frac{21}{2}$

= 10.5 m²

Area of the trench = Area of garden with trench - Area of garden

Put the value in the above

Area of the trench = 10.5 m² - 5 m²

= 5.5 m ²

Therefore the area of a trench is 5.5 m² .

5 0

3 years ago

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What is the mass (in grams) of 8.11×1026 CO2 molecules?

Kobotan [32]

Answer:

It is 59,275.74 grams

Step-by-step explanation:

• Molecular mass of carbon dioxide

$= (12 \times 1) + (16 \times 2) \\ = 12 + 32 \\ = 44 \: g$

[ molar masses: C = 12 g, O = 16 g ]

• From avogadro's number, it says 1 mole contains 6.02 × 10^23 molecules or atoms.

But 1 mole is equivalent to its molar mass in terms of weight, therefore;

${ \sf{6.02 \times {10}^{23} \: molecules = 44 \: g }}\\ { \sf{8.11 \times {10}^{26} \: molecules =( \frac{8.11 \times {10}^{26} }{6.02 \times {10}^{23} } \times 44) \: g}} \\ \\ = { \boxed{ \boxed{ \bf{59275.7 \: \: g}}}}$

6 0

3 years ago