Answer:
Rational exponents are not defined when the denominator of the exponent in lowest terms is even and the base is negative.
Step-by-step explanation:
Considering the expression
![X^{\frac{a}{b}}=\sqrt[b]{X^a};\:\:\:\:\:\:\:\:\:b\ne 0](https://tex.z-dn.net/?f=X%5E%7B%5Cfrac%7Ba%7D%7Bb%7D%7D%3D%5Csqrt%5Bb%5D%7BX%5Ea%7D%3B%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3Ab%5Cne%200)
Here:
A rational exponent - an exponent that is a fraction - is the kind of way we may write a root.
If the denominator is an even number, it means we are talking about an even root like square root, 4th root, 6th root etc.
For example, think about squaring a number
-4 × -4 = 16, 4 × 4 = 16
It means any number when it get multiplied by itself an even number of times, it would always yield a positive number.
It is not possible to take the square root of a negative number as we can not yield a negative number when we square the number. In other words, there is no way we can multiply the same negative number twice and get a negative number. This is why
is undefined.
Therefore, rational exponents are not defined when the denominator of the exponent in lowest terms is even and the base is negative.
A, you need to plug in to start solving
Answer:
?
Step-by-step explanation:
your answer is 1 ............................................
Answer:
No, you should have learned this in 5th grade
Step-by-step explanation: