Factor this and find all roots

The volume of a cone is 1540cm³. If its radius is 7cm, calculate the height of the cone. (Take pi = 22/7)

Ann [662]

Answer:

$h=30$

Step-by-step explanation:

Volume of a cone=1540 $cm^{3}$ , Radius=7cm.

The height of a cone=h

When we need to find the height of a cone, we can use the formula of the volume of a cone, which is $\frac{1}{3} \pi r^{2} h$ to find the height of a cone.

$1540cm^{3} =\frac{1}{3}\pi r^{2} h$

Put the pi value=22/7 and the value of radius which is 7 cm into the formula.

$1540cm^{3}=\frac{1}{3}*\frac{22}{7} 7^{2}h$

$1540cm^{3} =\frac{154}{3}h$

Move $\frac{154}{3}$ to another side. 1540 divided by $\frac{154}{3}$ to calculate what is the value of h, h is the height of a cone. Like this.

$\frac{1540cm^{3} }{\frac{154}{3} } =h$

$30=h$

Rearrange the h.

$h=30$

I hope you will understand my solution and explanation. If you still cannot get the point, you can ask me anytime! Thank you!

4 0

3 years ago

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HELPPPPPPPPPPPPPPPPPPPPPPPPPP

nevsk [136]

I think the answer is: -4.25

3 0

2 years ago

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A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0

3 years ago

How to evaluate 8x for each value of x for x=0.5

8090 [49]

8x will equal 4 because i multiplied both together.<span />

6 0

3 years ago

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What’s the answer<br><br><br> 5n-2=n+18

Sauron [17]

5n-2=n+18

Move n to the other side

Sign changes from +n to -n

5n-n-2= n-n+18

5n-n-2= 18

4n-2= 18

Move -2 to the other side

Sign changes from -2 to +2

4n-2+2= 18+2

4n= 18+2

4n= 20

Divide by 4 for both sides

4n/4= 20/4

Answer: n=5

4 0

3 years ago

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