Question

A square has a side length of 4a. One dimension is decreased by 5 and the other dimension is decreased by 5. Expand and simplify the expression that represents the area of the resulting rectangle

Answer 1

Answer:

$Area= 16a^2-40a+25$

Step-by-step explanation:

given that the side of the square is 4a

The expression for the area can be solved by

1. subtracting 5 from the sides of the square i.e (4a-5)

2. Solving for the area of the square using

$Area= l^2$

$Area= (4a-5)^2\\Area= (4a-5)(4a-5)$

opening the bracket and expending we have

$Area= 16a^2-20a-20a+25\\Area= 16a^2-40a+25$

the expression is $Area= 16a^2-40a+25$