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3 years ago

Which unit of measurement related to quantity

Computers and Technology

2 answers:

Phantasy [73]3 years ago

8 0

Answer:

The unit of measure that is related to the quantity is =

<u>Magnitude: Quantity * Unit of measurement.</u>

Explanation:

The word "Quantity" means a mathematical value that is given something that is measurable and represents the count of the number of elements that exist in a set.

Therefore, it can be said that the quantities are more, less or equal between them. And they can be represented by systems of units such as mass, weight or speed.

The formula <u>Magnitude = Quantity * Unit</u> of measurement is the number that exists of something by the measurement that is wanted to find of this.

For example, "20 kg" is the result of measuring something with respect to weight.

Lisa [10]3 years ago

6 0

Answer:

Unit: A standard quantity against which a quantity is measured [e.g. gram, metre, second, litre, pascal; which are units of the above quantities].

Hope This Helps! :) ;)

Explanation:

Source:

https://www.canterbury.ac.nz/media/documents/science-documents/Measurement.pdf

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Write the constructor for the Theater class. The constructor takes three int parameters, representing the number of seats per ro

sp2606 [1]

Answer:

See explaination

Explanation:

class Seat {

private boolean available;

private int tier;

public Seat(boolean isAvail, int tierNum)

{ available = isAvail;

tier = tierNum; }

public boolean isAvailable() { return available; }

public int getTier() { return tier; }

public void setAvailability(boolean isAvail) { available = isAvail; } }

//The Theater class represents a theater of seats. The number of seats per row and the number of tier 1 and tier 2 rows are

//determined by the parameters of the Theater constructor.

//Row 0 of the theaterSeats array represents the row closest to the stage.

public class Theater {

private Seat[][] theaterSeats; /** Constructs a Theater object, as described in part (a). * Precondition: seatsPerRow > 0; tier1Rows > 0; tier2Rows >= 0 */

public Theater(int seatsPerRow, int tier1Rows, int tier2Rows) {

theaterSeats= new Seat[tier1Rows+tier2Rows][seatsPerRow];

}

public boolean reassignSeat(int fromRow, int fromCol, int toRow, int toCol) {

if(theaterSeats[toRow][toCol].isAvailable()) {

int tierDestination =theaterSeats[toRow][toCol].getTier();

int tierSource =theaterSeats[fromRow][fromCol].getTier();

if(tierDestination<=tierSource) {

if(tierDestination==tierSource) {

if(fromRow<toRow) {

return false;

}else {

theaterSeats[toRow][toCol].setAvailability(false);

theaterSeats[fromRow][fromCol].setAvailability(true);

return true;

}

theaterSeats[toRow][toCol].setAvailability(false);

theaterSeats[fromRow][fromCol].setAvailability(true);

return true;

}else {

return false;

}

}else {

return false;

}

public static void main(String[] args) {

//Lets understand it with simple example

Theater t1 = new Theater(3,1,2);

//Our threater has 3 seat in each row and we have one tier 1 row and 1 tier 2 row

//total no of seat will be 9.

//Lets create our seat

t1.theaterSeats[0][0] = new Seat(true,1);

t1.theaterSeats[0][1] = new Seat(false,1);

t1.theaterSeats[0][2] = new Seat(true,1);

t1.theaterSeats[1][0] = new Seat(true,2);

t1.theaterSeats[1][1] = new Seat(true,2);

t1.theaterSeats[1][2] = new Seat(true,2);

t1.theaterSeats[2][0] = new Seat(false,2);

t1.theaterSeats[2][1] = new Seat(false,2);

t1.theaterSeats[2][2] = new Seat(true,2);

//Lets print out theater and see which seat is available or which is not

System.out.println("Theater===>");

for(int i=0;i<3;i++) {

for(int j=0;j<3;j++) {

System.out.print("["+i+"]"+"["+j+"] : "+t1.theaterSeats[i][j].isAvailable()+" ");

}

System.out.println();

}

System.out.println("(2,1) want to change seat to (0,0)");

System.out.println("["+2+"]"+"["+1+"]"+"===>"+"["+0+"]"+"["+0+"]");

t1.reassignSeat(2, 1, 0, 0);

for(int i=0;i<3;i++) {

for(int j=0;j<3;j++) {

System.out.print("["+i+"]"+"["+j+"] : "+t1.theaterSeats[i][j].isAvailable()+" ");

}

System.out.println();

}

5 0

4 years ago

Your online actions can have real- world consequences. True or false?

EastWind [94]

Answer:

This is very often false. It's not like anyone knows where you are when you're online, so they really cannot do much about your actions. However, there are times where this is true.

3 0

2 years ago

Read 2 more answers

use the internet to research the SYSTEM account. Why is it nessesary to include this account with full control on a directory

Kobotan [32]

Answer:

It is essential for the existence of a helicopter administration over all other users on the system.

Explanation:

A system account is a computer user account that is generated by an operating system (OS) during installation of the OS and that is utilized by the user in accordance to the parameters with which it has been designed and the purpose which it was created.

A System account is usually referred to as a privileged account because it comes with full control on one or more directories. A directory is simply a location for file storage on a computer. Full access or control includes the ability to:

read directories
write to directories
make changes to and delete files, folder and subfolders.
alter authorization settings for all files and subdirectories.

Besides control on the directory level, System Accounts which are also called Super Accounts which in addition to the above have permission to

install and remove software applications
update and or upgrade the computers operating system
access directories and files which normal users cannot and should not.

System Accounts are therefore important for security reasons. They are configured to act as a supervisory account which can create, authorise and terminate other accounts and processes.

Some of their merits include the ability to:

Oversee, audit, and completely control all other privileges.
forestall cyber attacks on the system from internal users or insiders.
Establish and provide evidence for compliance with regulatory codes

Cheers

8 0

3 years ago

Create a Java program with threads that looks through a vary large array (100,000,000 elements) to find the smallest number in t

olchik [2.2K]

Answer:

See explaination

Explanation:

import java.util.Random;

public class Sample{

static class MinMax implements Runnable{

int []arr;

int start,end,min,max;

MinMax(int[]arr, int start,int end){

this.start=start;

this.end=end;

min=Integer.MAX_VALUE;

max=Integer.MIN_VALUE;

this.arr=arr;

}

atOverride

public void run() {

for(int i=start;i<=end;i++){ //search min and max form strant to end index

min=Math.min(min,arr[i]);

max=Math.max(max, arr[i]);

}

public static void main(String[] args) throws Exception{

long beginTime = System.nanoTime();

Random gen = new Random();

int n=100000000;

int[] data = new int[n]; //generate and fill random numbers

for(int i = 0; i < data.length; i++) {

data[i] = gen.nextInt()%1000000;

}

long endTime = System.nanoTime();

System.out.println("Done filling the array. That took " + (endTime - beginTime)/1000000000f + " seconds.");

//-----------------------------------------

System.out.println("Using 1 thread"); //1 thread

MinMax m1=new MinMax(data,0,n-1); //class object

Thread t1=new Thread(m1); //new thread

beginTime=System.nanoTime(); //start timer

t1.start(); //start thread

t1.join(0); //wait until thread finishes

endTime=System.nanoTime(); //end timer

System.out.println("Min,Max: "+m1.min+","+m1.max); //print minimum and maximum

System.out.println("Time using 1 thread " + (endTime - beginTime)/1000000000f + " seconds."); //print time taken

//-----------------------------------------

System.out.println("Using 2 thread");

m1=new MinMax(data,0,n/2);

MinMax m2=new MinMax(data,n/2+1,n-1);

t1=new Thread(m1);

Thread t2=new Thread(m2);

beginTime=System.nanoTime();

t1.start();

t2.start();

t1.join(0);

t2.join(0);

endTime=System.nanoTime();

System.out.println("Min,Max: "+ Math.min(m1.min,m2.min)+","+Math.max(m1.max,m2.max));

System.out.println("Time using 2 thread " + (endTime - beginTime)/1000000000f + " seconds.");

//-----------------------------------------

System.out.println("Using 3 thread");

m1=new MinMax(data,0,n/3);

m2=new MinMax(data,n/3+1,2*n/3);

MinMax m3=new MinMax(data,2*n/3+1,n-1);

t1=new Thread(m1);

t2=new Thread(m2);

Thread t3=new Thread(m3);

beginTime=System.nanoTime();

t1.start();

t2.start();

t3.start();

t1.join(0);

t2.join(0);

t3.join(0);

endTime=System.nanoTime();

System.out.println("Min,Max: "+ Math.min(Math.min(m1.min,m2.min),m3.min)+","+Math.max(Math.max(m1.max,m2.max),m3.max));

System.out.println("Time using 3 thread " + (endTime - beginTime)/1000000000f + " seconds.");

//-----------------------------------------

System.out.println("Using 4 thread");

m1=new MinMax(data,0,n/4);

m2=new MinMax(data,n/4+1,2*n/4);

m3=new MinMax(data,2*n/4+1,3*n/4);

MinMax m4=new MinMax(data,3*n/4+1,n-1);

t1=new Thread(m1);

t2=new Thread(m2);

t3=new Thread(m3);

Thread t4=new Thread(m4);

beginTime=System.nanoTime();

t1.start();

t2.start();

t3.start();

t4.start();

t1.join(0);

t2.join(0);

t3.join(0);

t4.join(0);

endTime=System.nanoTime();

System.out.println("Min,Max: "+ Math.min(Math.min(m1.min,m2.min),Math.min(m3.min,m4.min))+","+Math.max(Math.max(m1.max,m2.max),Math.max(m3.max,m4.max)));

System.out.println("Time using 4 thread " + (endTime - beginTime)/1000000000f + " seconds.");

}

6 0

3 years ago

Threads in the ____ are idle, pending availability of a cpu.

slava [35]

Run queue. They can also be waiting on I/O.

7 0

4 years ago