Answer:
User can make the network name
Answer:
// C++ program to find k largest elements in the array
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variable
int n,k;
cout<<"Enter the number of elements of array:";
// read the value of n
cin>>n;
// declare the array of size n
int arr[n];
cout<<"Enter the elements of array:";
// read the elements of array
for(int a=0;a<n;a++)
{
cin>>arr[a];
}
cout<<"Enter the value of K:";
cin>>k;
// call the function to perform selection Sort
sort(arr, arr+n);
cout << k<<" largest elements of the array are: ";
// print k largest elements of the array
for (int i=n-1; i>n-k-1; i--)
cout << arr[i] << " ";
return 0;
}
Explanation:
Read the number of elements in the array.Then create an array of size "n" and read n elements of the array.Sort the array in ascending array.Then Read the value of k from user.Find the k Elements from the end of the array.This will be the k largest elements of the array.
Output:
Enter the number of elements of array:8
Enter the elements of array:34 8 75 99 12 7 5 55
Enter the value of K:3
3 largest elements of the array are: 99 75 55
Answer:
<em>This program is written in C++</em>
<em>Comment are used to explain difficult lines</em>
<em>The first program that prints 0 to 20 (in decimal) starts here</em>
#include<iostream>
int main()
{
//Print From 0 to 20
for(int i = 0;i<21;i++)
{
std::cout<<i<<'\n';
}
}
<em>The modified program to print 0 to 20 in hexadecimal starts here</em>
#include<iostream>
using namespace std;
int main()
{
//Declare variables to use in conversion;
int tempvar, i=1,remain;
//Declare a char array of length 50 to hold result
char result[50];
//Print 0
cout<<"0"<<endl;
// Iterate from 1 to 20
for(int digit = 1; digit<21; digit++)
{
//Start Conversion Process
//Initialize tempvar to digit (1 to 20)
tempvar = digit;
while(tempvar!=0)
{
//Divide tempvar by 16 and get remainder
remain = tempvar%16;
if(remain<10)
{
result[i++]=remain + 48;
}
else
{
result[i++] = remain + 55;
}
//Get new value of tempvar by dividing it by 16
tempvar/=16;
}
//Print result
for(int l=i-1;l>0;l--)
{
cout<<result[l];
}
i=1;
cout<<endl;
}
return 0;
}
//The Program Ends Here
See Attachments for program 1 and 2; program 2 is the modified version of 1
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cpp
</span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
cpp
</span>
Answer:
126.375 in binary is: 1111110.011
Explanation:
In order to convert a decimal number to binary number system, the integral part is converted using the division and remainder method while the fractional part is multiplied with 2 and the integral part of answer is noted down. The fractional part is again multiplied with 2 and so on.
For 126.375
2 126
2 63 - 0
2 31 - 1
2 15 - 1
2 7 - 1
2 3 - 1
1 - 1
So, 126 = 1111110
For 0.375
0.375 * 2 = 0.75
0.75 * 2 = 1.5
0.5 * 2 = 1.0
As we had to only find 3 digits after binary point, so
0.375 = 011
So 126.375 in binary is: 1111110.011 ..
