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yarga [219]
2 years ago
6

Select the correct answer. Which statement is true with respect to Java?

Computers and Technology
1 answer:
NARA [144]2 years ago
7 0

Answer:

where are the options ..... to select

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Your friend Amy calls you asking for help with her new LCD monitor. She says the monitor isn't showing the whole picture. What i
swat32

Answer:     probably 1080p (which is HD)

Explanation:    Lcd monitors mainly support 1080p.

3 0
3 years ago
Just a quick question, how do you set something == to char and int in an if statement (java)
Troyanec [42]

This is the requested code in java.

public class <em>CharTest</em> {

   public static String checkCharacter(String text, int index) {

       if (0 <= index && index <= text.length()) {

           char ch = text.charAt(index);

           if (Character.isLetter(ch)) {

               return ch + " is a letter";

           } else if (Character.isDigit(ch)) {

               return ch + " is a digit";

           } else if (Character.isWhitespace(ch)) {

               return ch + " is a whitespace character";

           } else {

               return ch + " is an unknown type of character";

           }

       } else {

           return "index " + index.toString() + " is out of range";

       } // <em>end if</em>

   } // <em>end function checkChar()</em>

   public static void <em>main</em>(String[] args) {

       // <em>Test the three samples from the specification.</em>

       System.out.println(<em>checkCharacter</em>("happy birthday", 2));

       System.out.println(<em>checkCharacter</em>("happy birthday", 5));

       System.out.println(<em>checkCharacter</em>("happy birthday 2 you", 15));

   } // <em>end function main()</em>

} // <em>end class CharTest</em>

The function <em>checkcharacter</em>(text, index) returns a string value describing the kind of character found at the position in text specified by index; whether it was a letter, digit, whitespace, or an unknown kind of character.

How it does that is to make use of respective functions defined within the Character class in java. That is

  • isLetter(char) returns a bool specifying if the char parameter is a letter.
  • isDigit(char) returns a bool specifying if the char parameter is a digit.
  • isWhitespace(char) returns a bool specifying if the char parameter is a whitespace character.

It calls these functions in an if statement. These else part of the if statement is then executed if the character is neither a <em>letter</em>, <em>digit</em>, or <em>whitespace</em>.

Finally, the function main() calls <em>checkCharacter</em>() three times to test the function and return the results to the console.

Another example of a java program on characters is found in the link below

brainly.com/question/15061607

3 0
2 years ago
What is a way of telling the computer how to display certain content pls answer quick
coldgirl [10]
Machine language is the language understood by a computer. It is very difficult to understand, but it is the only thing that the computer can work with. All programs and programming languages eventually generate or run programs in machine language
4 0
3 years ago
It is possible to collaborate on a presentation with a group of people using the Internet.
DerKrebs [107]

Answer:

True

Explanation:

4 0
3 years ago
Program:
Mkey [24]

Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

print('s - Shorten spaces')

print('q - Quit\n')

#getting choice

choice=input('Choose an option: ').lower()

#identifying choice

if choice=='c':

#displaying number of non white space chars in input_str

print('Number of non-whitespace characters:',get_num_of_non_WS_characters(input_str))

elif choice=='w':

#displaying number of words in input_str

print('Number of words:',get_num_of_words(input_str))

elif choice=='f':

#fixing capitalization and getting updated string and count of values capitalized

input_str,count=fix_capilization(input_str)

#displaying results

print('Number of letters capitalized:',count)

print('Edited text:',input_str)

elif choice=='r':

#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

print('Edited text:', input_str)

elif choice=='s':

#shortening spaces and displaying updated text

input_str = shorten_space(input_str)

print('Edited text:', input_str)

#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

#i is not a space

count+=1

return count

#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

words=input_str.split(' ')

count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

return count

#method to fix capitalization and return updated string and count of letters updated

def fix_capilization(input_str):

count=0

beginning=True #starting letter should be capitalized

result=''

for i in input_str:

if beginning and i.isalpha():

#start of a sentence and i is alphabetic

if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

count+=1

result+=i

#not start of a sentence

beginning=False

elif i in '?.!':

#i is either ? or . or !, next letter should be capitalized

beginning=True

result+=i

else:

#any other character

result+=i

return result,count

#method to replace exclamation and semicolons with period and comma respectively

def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

if i=='!':

i='.'

exclamationCount+=1

elif i==';':

i=','

semicolonCount+=1

result+=i

print('Punctuation replaced')

#displaying replaced values counts

print('exclamationCount:',exclamationCount)

print('semicolonCount:',semicolonCount)

return result

#removes all double or more spaces in input_str

def shorten_space(input_str):

input_str=input_str.strip()

result=''

prev=None

for i in input_str:

if prev==None:

result+=i

elif i==' ':

if prev != ' ':

result+=i

else:

result+=i

prev=i

return result

if __name__ == '__main__':

#getting input, printing it

input_str=input('Enter a sample text:\n')

print('\nYou entered:',input_str)

choice=' '

#looping until choice becomes q

while choice!='q':

choice,input_str=print_menu(input_str)

7 0
3 years ago
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