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4 years ago

A cyclist accelerates at a rate of 7.0 m/s2. how long will it take the cyclist to reach a speed of 18 m/s?

2 answers:

8 0

At constant acceleration the equation is

v = u + at where u = initial speed, a = acceleration. t = time and v = final speed

So here we have 18 = 0 + 7t

t = 18/7 = 2.6 seconds ( to nearest tenth)

Delvig [45]4 years ago

5 0

Answer:

2.57 seconds

Step-by-step explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

Before we can solve this question we need to create a formula that calculates the final speed. The formula will be the following,

$Vf = Vi+7(t)$

Where:

Vf is the final Velocity
Vi is the initial velocity
A is the acceleration
t is the time in seconds

Now that we have the formula we can plug in the values given to us in the question and solve for the amount of time (t).

$Vf = Vi+7(t)$

$18 = 0+7(t)$

$2.57 = t$

Finally, we can see that it would take the cyclist 2.57 seconds (approximately) to reach a speed of 18 m/s

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Answer:

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Step-by-step explanation:

Previous concepts

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In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

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The margin of error for the proportion interval is given by this formula:

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And on this case we have that $ME =\pm 0.05$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

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