Find the range of the data set 145, 612, 120, 349, 515, 212, 590.
2 answers:
You might be interested in
K = 1.2 Short answer.
It's going to seem odd, but one of the ways you could solve this is by multiplying the first equation by 4. I'll tell you why in a moment.
4(0.3x - 0.7y = 1) Now remove the brackets.
1.2x - 2.8y = 4 If you want there to be no solution, the way to do it is the make k = 1.2 The second equation becomes.
1.2x - 2.8y = 3
I'm going to give you the graph of this so you will see why there is no solution. Do you see why?
The lines are parallel!! they never meet.
It's going to seem odd, but one of the ways you could solve this is by multiplying the first equation by 4. I'll tell you why in a moment.
4(0.3x - 0.7y = 1) Now remove the brackets.
1.2x - 2.8y = 4 If you want there to be no solution, the way to do it is the make k = 1.2 The second equation becomes.
1.2x - 2.8y = 3
I'm going to give you the graph of this so you will see why there is no solution. Do you see why?
The lines are parallel!! they never meet.
Answer:
E'F' and EF are equal in length
Step-by-step explanation:
we have
The coordinates of point E(-3,2) and F(-1,2)
we know that
The rule of the reflection across the x-axis is
(x,y) ------> (x,-y)
so
Applying the rule of reflection across the x-axis
E(-3,2) -------> E'(-3,-2)
F(-1,2) --------> F'(-1,-2)
using a graphing tool
see the attached figure to better understand the problem
therefore
E'F' and EF are equal in length
