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MArishka [77]
2 years ago
6

Find the range of the data set 145, 612, 120, 349, 515, 212, 590.

Mathematics
2 answers:
Kamila [148]2 years ago
7 0

Answer:

612 - 120=492

Step-by-step explanation:

to find the range the formula is to list the data set from smallest to largest, then subtract the smallest from the largest. 120, 145, 212, 349, 515, 590, 612= 612 - 120= 492

storchak [24]2 years ago
6 0

Answer:

The biggest - the smallest

612-120=492

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30

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What is the length of AC?
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The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she d
aksik [14]

Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

<h3 /><h3>Step 1</h3>

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

f(t)=\left \{ {{0 ,\-t

Consider the second function:

f(t)=\frac{e^{-t/\mu}}{\mu}\\

Where Average waiting time = μ = 2.5

The function f(t) becomes

f(t)=0.4e^{-0.4t}

<h3>Step 2</h3>

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt

which is equal to 0.01

<h3>Step 3</h3>

Solve the equation for x

\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01

Take natural log on both sides

ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53

<h3>Results</h3>

The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger

3 0
3 years ago
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As we do not know the other cars avg speed we can not tell the answer. Please repeat the question.

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You'd find this problem easier to understand and do if you'd please list the defining equations vertically and line up variables:

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Thus, -3z = 6, and z = -2.

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