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SpyIntel [72]
3 years ago
8

The conclusion to an experiment often includes new questions to be tested. This is why science is considered to be _____. A. dif

ficult B. a cycle C. repeatable D. testable
Physics
1 answer:
Veronika [31]3 years ago
6 0
I would say D. Testable
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What is the frequency of the fundamental mode of vibration of a steel piano wire stretched to a tension of 440 N? The wire is 0.
algol [13]

Answer:

<h2><em>220.698Hz</em></h2>

Explanation:

The fundamental frequency f₀ is expressed as f₀ =V/2L where;

V is the speed of the string = \sqrt{\frac{T}{M} }

m is the mass of the string

L is the length of the string

T is the tension in the string

f₀ = \frac{1}{2L} \sqrt{\frac{T}{m} }

Given datas

m = 5.69g = 0.00569 kg

T = 440N

L = 0.630 m

Required

Fundamental frequency of the steel piano wire f₀

f_0 = \frac{1}{2(0.630)}\sqrt{\frac{440}{0.00569} } \\ \\f_0 =  \frac{1}{1.26}\sqrt{77,328.65 } \\\\f_0 = \frac{1}{1.26} * 278.08\\\\f_0 = 220.698Hz

<em>Hence the frequency of the fundamental mode of vibration of the steel piano wire stretched to a tension of 440N is 220.698Hz</em>

3 0
3 years ago
Mr. Galonski loves to use the electromagnetic spectrum. Create a scenario in his everyday life. Your scenario must include at le
My name is Ann [436]

-- Mr. Galonski looks at himself in the mirror while he shaves in the morning, using visible light.

-- On his way to work, he listens to music and news, taking advantage of all the radio waves around.

-- While walking from his car to his office, he takes his jacket off and rolls up his sleeves, so his arms can soak up some ultraviolet from the sun, and get a little bit of color.

-- Mister Galonski is actually DOCTOR Galonski DDS ... a dentist. He uses a machine that produces X-rays, to take pictures of his patients' teeth and jaws. He glues the pictures into a big scrap-book that he keeps on the coffee table in his living room.

8 0
3 years ago
What is background radiation?
IceJOKER [234]
The uniform microwave radiation remaining from the Big Bang 
7 0
3 years ago
Calculate the p.e. of a 5 kg mass when it is (i) 3 m, (ii) 6 m, above the ground. (g = 10 N/kg)​
Mashcka [7]

Explanation:

P.E=MGH

(1) P.E=5×10(G)×3

= 150 kg m^/s^ ( ^ =sqaure)

(2) P.E=5×10×6

= 300 kg m^/s^

Hope it helps, just remember the formula u can solve any question regarding gravition of earth (P.E=Mgh)

4 0
3 years ago
Object A has of mass 7.20 kilograms, and object B has a mass of 5.75 kilograms. The two objects move along a straight line towar
Vera_Pavlovna [14]
If the collision is elastic, there is no loss in kinetic energies, which means that the total energies before and after impact are the same.  So no need to worry about final velocities.

Final energy
= initial energy
= (1/2) (7.20*2.00^2+5.75*(-1.30)^2)
=19.26 joules

Answer: the total kinetic energy is 19.3 J. after collision.

8 0
4 years ago
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