Answer:
The maximum safe speed of the car is 30.82 m/s.
Explanation:
It is given that,
The formula that models the maximum safe speed, v, in miles per hour, at which a car can travel on a curved road with radius of curvature r r, is in feet is given by :
.........(1)
A highway crew measures the radius of curvature at an exit ramp on a highway as 380 feet, r = 380 feet
Put the value of r in equation (1) as :

v = 30.82 m/s
So, the maximum safe speed of the car is 30.82 m/s. Hence, this is the required solution.
Answer:3.56 nanosecond
In this case, you are asked the time and given the light distance(3.5ft)
To answer this question you would need to know the velocity of light. Speed of light is <span>299792458m/s. Then the calculation would be:
time= distance/speed
time= 3.5 ft / (</span>299792458m/s) x 0.3048 meter/ 1 ft= 3.56

second or 3.56 nanosecond
Yo sup??
we should know that
work done=force*displacement
W=F.s
F=10 N
s=8 m
therefore
W=10*8
=80 N
Hope this helps.