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tatuchka [14]
4 years ago
9

A basketball weighs an average of 22 ounces, and it is possible for its weight to vary at most 0.75 ounces from this average. Wh

at’s the range for a basketball weight?
Mathematics
1 answer:
Zanzabum4 years ago
3 0

Answer:

21.25 - 22.75

Step-by-step explanation:

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Judys brother sam has a collection of 96 comic book. What are the ten way sam could divide his comic books into equal groups?
Georgia [21]
We have been given that Judy’s brother Sam has a collection of 96 comic books.
We have been asked to find the 10 ways Sam could divide his comic books into equal groups.
This can be done as follows:
96 can be written as .
Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.
Likewise, 96 can also be written as . Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.
Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a total of 10 ways in which Sam can divide his comic books into equal groups.
4 0
3 years ago
Solve: 12.5 z – 6.4 = –8 z + 3(1.5 z – 0.5)
dolphi86 [110]

Answer:

Step-by-step explanation:

12.5z - 6.4 =-8z + 3(1.5z - 0.5)

12.5z - 6.4 = - 8z + 4.5z - 1.5

12.5z - 6.4 = - 3.5z - 1.5

Bringing like terms on one side

12.5z + 3.5z = - 1.5 + 6.4

16z = 4.9

z = 4.9/16

6 0
3 years ago
Jamie took an 8-week keyboarding class. At the end of each week, she took a test to find the number of words she could type per
Bingel [31]
She improved about 4.3 words per min each week
6 0
4 years ago
A rumor spreads through a small town. Let y ( t ) be the fraction of the population that has heard the rumor at time t and assum
Ivan

Answer:

Differential equation

\frac{dy}{dt} =ky(1-y)

Solution

y=\frac{1}{1+4e^{-0.327t}}

Value of constant k=0.327 days^(-1)

The rumor reaches 80% at 8.48 days.

Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

y'(t)=ky(1-y), rate of spread of the rumor

Differential equation

\frac{dy}{dt} =ky(1-y)

Solving the differential equation

\frac{dy}{y(1-y)}=k\cdot dt \\\\\int \frac{dx}{y(1-y)} =k \int dt \\\\-ln(1-\frac{1}{y} )+C_0=kt\\\\1-\frac{1}{y} =Ce^{-kt}\\\\\frac{1}{y} =1-Ce^{-kt}\\\\y=\frac{1}{1-Ce^{-kt}}

Initial conditions:

y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48

The rumor reaches 80% at 8.48 days.

8 0
3 years ago
Using tour answer from base e, ale
Natasha2012 [34]

That’s all correct thanks

5 0
3 years ago
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