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quester [9]
3 years ago
5

What is one way to evaluate information from the media?

Mathematics
2 answers:
kifflom [539]3 years ago
6 0

Answer: The answer is (D) distinguish between fact and opinion.

Step-by-step explanation: We are given four options out of which we are to select the correct way to evaluate information from the media.

To evaluate information from the media, we just need to remember two important things about the incident. The first one is the fact and the second one is the opinion, so that we can easily distinguish between both of them and get any information from the media.

Thus, the correct option is (D).

notka56 [123]3 years ago
3 0

Answer:

D) distinguish between fact and opinion

Step-by-step explanation:

A. Slogans usually don't provide much information, so memorizing them wouldn't do much towards evaluating information.

B. By asking people what they think, you are prone to get their personal opinions, which could be biased and, therefore, not relevant to evaluating information from the media.

C. Viewing only parts of programs can lead to getting incomplete information, which would hinder its evaluation.

D. Distinguish between fact and opinion is essential to evaluate information from the media in order to base your evaluations on the facts without opinion biases.

The answer is D)

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You increase the size of a page by 30%. Then you decrease it by 30%. What is the size of the page now?
kotegsom [21]
Lets use 1 to solve this problem because it is easiest to show. 

Multiply 1 by 1.3 for a 30% increase (1*1.3=1.3). 

Then multiply 1.3 by .7 for a 30% decrease. (1.3*.7=.91)  

Therefore the page had a 9% reduction from its original size or is 91% of its original size. 
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3 years ago
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Explain how you can use equivalent fractions to find the quotient of 2 3 ÷ 4.
Virty [35]

Answer:

see below

Step-by-step explanation:

2/3 ÷ 4

We use copy dot flip

The flip means make a reciprocal of the second number

2/3 * 1/4

Multiply the numerators

2*1 = 2

Multiply the denominators

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Put the numerator over the denominator

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3 years ago
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An amusement park offers two options. Option 1 involves a $10 admission fee plus $0.50 per ride. Option 2 involves a $6 admissio
Art [367]

Answer:

16 rides

Step-by-step explanation:

Option 1 . Admission fee = $10

                Each ride = $0.50

Option 2 . Admission fee = $6

                Each ride = $0.75

Let no. of rides be x

So, cost of ride according to option 1 = 0.50x

So, total cost after having x rides according to option 1 :

= 10+0.50x  ---1

Cost of ride according to option 2 = 0.75x  

So, total cost after having x rides according to option 2 :

= 6+0.75x  --2

Now to find the beak even point i.e. having the same cost

Equate 1 and 2

10+0.50x=6+ 0.75x

10-6= 0.75x-0.50x

4= 0.25x

\frac{4}{0.25} =x

16=x

Thus for 16 rides , the two options have the same cost .

Hence the break even point is 16 rides

5 0
4 years ago
g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur
sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

\displaystyle V = \pi r^2h

Substitute:

\displaystyle (300) = \pi r^2 h

Solve for <em>h: </em>

\displaystyle \frac{300}{\pi r^2} = h

Recall that the surface area of a cylinder is given by:

\displaystyle A = 2\pi r^2 + 2\pi rh

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r}  \end{aligned}

Find its derivative:

\displaystyle A' = 4\pi r - \frac{600}{r^2}

Solve for its zero(s):

\displaystyle \begin{aligned} (0) &= 4\pi r  - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

\displaystyle  \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2}  \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm}   \end{aligned}

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

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Answer:a lot

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