Help me please i am confused on what to do
2 answers:
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The picture in the attached figure
Part 1) <span>What is the total area of the swimming pool?
</span>
we know that
<span>area of the swimming pool=area rectangle-area semi circle
area rectangle=20*36-----> 720 ft</span>²
area semicircle=pi*r²/2
r=18/2----> 9 ft
area semicircle=pi*9²/2----> 127.17 ft²
area of the swimming pool=720 ft²-127.17 ft²----> 592.83 ft²
the answer Part 1) is
The area of the swimming pool is 592.83 ft²
Part 2) <span>What is the perimeter of the swimming pool?
</span>
perimeter of the swimming pool=perimeter of rectangle-18 ft+perimeter semi circle
perimeter of rectangle=2*[20+36]---> 112 ft
perimeter semi circle=2*pi*r/2----> pi*r
r=9 ft
perimeter semi circle=pi*9----> 28.26 ft
so
perimeter of the swimming pool=112 ft-18 ft+28.26 ft----> 122.26 ft
the answer Part 2) is
122.26 ft
Part 1) <span>What is the total area of the swimming pool?
</span>
we know that
<span>area of the swimming pool=area rectangle-area semi circle
area rectangle=20*36-----> 720 ft</span>²
area semicircle=pi*r²/2
r=18/2----> 9 ft
area semicircle=pi*9²/2----> 127.17 ft²
area of the swimming pool=720 ft²-127.17 ft²----> 592.83 ft²
the answer Part 1) is
The area of the swimming pool is 592.83 ft²
Part 2) <span>What is the perimeter of the swimming pool?
</span>
perimeter of the swimming pool=perimeter of rectangle-18 ft+perimeter semi circle
perimeter of rectangle=2*[20+36]---> 112 ft
perimeter semi circle=2*pi*r/2----> pi*r
r=9 ft
perimeter semi circle=pi*9----> 28.26 ft
so
perimeter of the swimming pool=112 ft-18 ft+28.26 ft----> 122.26 ft
the answer Part 2) is
122.26 ft
The rate at which the water from the container is being drained is 24 inches per second.
Given radius of right circular cone 4 inches .height being 5 inches, height of water is 2 inches and rate at which surface area is falling is 2 inches per second.
Looking at the image we can use similar triangle propert to derive the relationship:
r/R=h/H
where dh/dt=2.
Thus r/5=2/5
r=2 inches
Now from r/R=h/H
we have to write with initial values of cone and differentiate:
r/5=h/5
5r=5h
differentiating with respect to t
5 dr/dt=5 dh/dt
dh/dt is given as 2
5 dr/dt=5*-2
dr/dt=-2
Volume of cone is 1/3 π
We can find the rate at which the water is to be drained by using partial differentiation on the volume equation.
Thus
dv/dt=1/3 π(2rh*dr/dt)+(*dh/dt)
Putting the values which are given and calculated we get
dv/dt=1/3π(2*2*2*2)+(4*2)
=1/3*3.14*(16+8)
=3.14*24/3.14
=24 inches per second
Hence the rate at which the water is drained from the container is 24 inches per second.
Learn more about differentaiation at brainly.com/question/954654
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