Answer: A cos (π/4)
I just took a test with this question and got it right
Answer:
Given : JKLM is a rectangle.
Prove: JL ≅ MK
Since, by the definition of rectangle all angles of rectangles are right angle.
Thus, In rectangle JKLM,
∠ JML and ∠KLM are right angles.
⇒ ∠ JML ≅ ∠KLM
Since, JM ≅ KL (Opposite sides of rectangles are congruent)
ML ≅ ML ( Reflexive )
Thus, By SAS congruence postulate,
Δ JML ≅ Δ KLM
⇒ JL ≅ MK ( because corresponding parts of congruent triangles are congruent)
Hence proved.
Answer:
Angle 1 = 41°
Step-by-step explanation:
Since they are both vertical angles
(6x+11)° = (10x-9)°
6x - 10x = -9 - 11
-4x = -20
4x = 20
x= 5.
Therefore,
Angle 1 = 6(5) + 11
Angle 1 = 30 + 11
Angle 1 = 41°
<span><span>2<span><span>(x+3)</span>2</span>+1</span><span>2<span><span>(x+3)</span>2</span>+1</span></span>Reorder the right side of the equation to match the vertex form of a parabola.<span><span>y=2<span><span>(x+3)</span>2</span>+1</span><span>y=2<span><span>(x+3)</span>2</span>+1</span></span>Use the vertex form, <span><span>y=a<span><span>(x−h)</span>2</span>+k</span><span>y=a<span><span>(x-h)</span>2</span>+k</span></span>, to determine the values of <span>aa</span>, <span>hh</span>, and <span>kk</span>.<span><span>a=2</span><span>a=2</span></span><span><span>h=−3</span><span>h=-3</span></span><span><span>k=1</span><span>k=1</span></span>Find the vertex <span><span>(h,k)</span><span>(h,k)</span></span>.<span>(−3,1<span>) ...................................</span></span>
